Butane is not a element. Butane has a molar mass.
First you need the molar mass of butane, which is C4H10: MM = 4 * 12.01 + 10 * 1.008 = 58.12 g/mol Since there are three moles of butane you get: 3.00 mol * 58.12 g/mol = 174 g (3 sig figs)
1 mole = 4 g of helium
So 3 moles = 12 g
Depends on what the substance is. 3 moles of hydrogen has less mass than 3 moles of calcium or 3 moles of water but they all have the same number of particles called Avogadro's number.
3 mol C2H60 (46.068g/1mol)=138.2 grams c2h6o
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
170 to 190 grams depending on pressure. ie sea level or higher...
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
170 to 190 grams depending on pressure. ie sea level or higher...
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
300 kilograms
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
418.4 grams.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
The estimated mass of 300 ml is about 300 grams. This can change based on the temperature and the density of the sample.
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
No formula, just dimensional analysis and ratios. Aspirin is C9H8O6 300 mg C9H8O6 (1 gram/1000 milligrams)(1 mole C9H8O6/212.154 grams) = 1.41 X 10^-3 moles aspirin just get milligrams up to grams and divide that by the molar mass
2300 grams 1 kilogram is 1000 grams