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How many moles of oxygen are needed to burn 7.0 mols of phosphorus?
8,75 moles of oxygen are needed.
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
How many moles of glucose will burn if we have 5 moles of CO 2 as a product?
0,83moles glucose are burned.
How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
What element in the air is needed for coal dust to burn?
Oxygen is the element in the air that is needed for coal dust to burn. When coal dust is exposed to oxygen and heat, it can ignite and burn.
How many moles of O2 are needed to burn 1.50 moles of C8H18?
The balanced equation for the combustion of C8H18 is: C8H18 + 12.5O2 -> 8CO2 + 9H2O From the equation, you need 12.5 moles of O2 to burn 1 mole of C8H18. So, to burn 1.50 moles of C8H18, you would need 1.50 x 12.5 = 18.75 moles of O2.
How many moles of oxygen are needed to burn 7.0 mols of phosphorus?
8,75 moles of oxygen are needed.
How many moles of O2 are needed to burn 10 moles of Mg?
A. A balance chemical equation of burning of ethene is C2H4 + 3O2 ____ 2CO2 + 2H2O now according to balance chemical equation 1 mole of ethene burn by using 3 moles of oxygen so to burn 10 moles of ethene 3 x 10 30 moles of oxygen will be required.
What weight of oxygen is required to completely burn 19.8 g of octane?
The chemical equation for complete burning of octane is: 2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O. This equation shows that 25 moles of diatomic oxygen are required to completely burn each two moles of octane. The gram molecular mass of octane is 114.23 and the gram molecular mass of diatomic oxygen is 2(15.9994). Therefore, the ratio of the mass of oxygen required to completely burn any given mass of octane to the mass of the octane to be burned is 50(15.9994)/2(114.23) or 3.5016, to the justified number of significant digits (the same as the number of digits in the least precisely specified datum 114.23, and the mass of oxygen required to burn 19.8 g of octane is (3.5016)(19.8) or 69.3 grams to the justified number of significant digits, now limited by the less precisely specified datum 119.8.
How many liters of oxygen are needed to burn 20 liters of hydrogen?
You need to state temperature and pressure of the gases I think, from this you can find the number of moles of both. The equation is 2H2 + O2 => 2H2O calculate the moles burned (for every 2 moles h2, 1 mole of O2 will burn.
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
Does fossil fuels produce carbon dioxide gas and water when they burn?
Yes, if they are perfectly pure and burn correctly. Otherwise there is additional nasty stuff in small quantities. Added: 2C8H18 + 25O2 --> 16CO2 + 18H2O A reaction showing the simplified burning of gasoline ( C8H18 = octane ) and the many moles of carbon dioxide and water produced.
Calculate with clear arrangements how many moles of oxygen are needed to burn 1 kg of ethane and 1 kg of ethanol, respectively?
nothing
How many moles of C3H8 are needed to react with 0.567 mol of 02?
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
How much oxygen is needed to ignite gasoline?
The combustion reaction of petrol is commonly 2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O. So for every two moles of petrol, 25 moles of oxygen are required. Thus for the 6.15 moles of gas, 153.75 moles of O2 are needed or 3440 liters.
How many grams of O2 are needed to completely burn 51.6 g of C3H8?
The balanced chemical equation for the combustion of propane (C3H8) is 1 C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means 5 moles of O2 are required for every 1 mole of C3H8. Calculate the moles of C3H8 in 51.6 g, then use the mole ratio to find the moles of O2 needed. Finally, convert the moles of O2 to grams.
How may grams of oxygen are required to burn 13.50 grams of acetylene?
To burn 1 mole of acetylene (C2H2), 3 moles of oxygen (O2) are required. The molar mass of acetylene is 26.04 g/mol and of oxygen is 32.00 g/mol. First, convert 13.50g acetylene to moles, calculate the moles of oxygen required, and then convert back to grams to find the mass of oxygen needed.
