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How many moles of C3H8 are needed to react with 0.567 mol of 02?
MaryGrimesfb6601
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
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What volume would be occupied by 2 moles of propane gas C3H8 at standard conditions?
1 mole of any gas at STP occupies 22.4 liters. Thus, 2 moles propane will occupy 2 x 22.4 L = 44.8 liters.
What is the word equation for prophane?
Propane ( C3H8 ) Will burn completely in excess oxygen to form water and carbon dioxide;C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
What are two compounds found in nature?
Compounds are a combination of two or more elements that form a molecule. Bonds can be covalent or ionic, and depend on the atoms involved. Natural compounds are atomic combinations found in nature and are created by natural processes. Carbon Dioxide (CO2) and Ammonia (NH3) are both natural compounds.
How many moles of oxygen are necessary to react completely with 4 moles of propane?
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
What is the total number of moles of O2(g) required for the complete combustion of 1.5 moles of C3H8(g)?
C3H8 + 5O2 ==> 3CO2 + 4H2O balanced equationmole ratio O2:C2H8 = 5:1 1.5 moles C3H8 x 5 moles O2/mole C3H8 = 7.5 moles O2 needed
If 5.0 moles of C3H8 react how many molecules of water are formed?
1.2x10^25
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
C3H8 plus 5O2---3CO2 plus 4H2O. How many moles of water form when 4.50 L propane gas C3H8 completely react?
5048+w4g5=23vm32
When 2.13 moles of C3H8 burn in excess oxygen how many moles of CO2 will be formed assuming complete combustion?
Out of one mole C3H8 three moles carbondioxide (CO2) are formed by complete combustion of it.So 2.13 mole C3H8 make 3*2.13 mole CO2 = 6.39 moleCO2
How many grams of oxygen are required to complete combustion of 2.75 moles of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
How many moles of oxygen are utilized by the complete combustion of propane?
Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.
How much oxygen is needed to ignite gasoline?
The combustion reaction of petrol is commonly 2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O. So for every two moles of petrol, 25 moles of oxygen are required. Thus for the 6.15 moles of gas, 153.75 moles of O2 are needed or 3440 liters.
What is the percent composition by mass of 1.2 moles of carbon and 3.2 moles of hydrogen?
If you think to propane (C3H8): carbon - 81,7 % and hydrogen - 17,3 %.
How many moles of O2 are needed to burn 1.50 moles of C8H18?
Balance this combustion reaction first! 2C4H10 + 13O2 -> 8CO2 + 10H2O 0.86 moles C4H10 (13 moles O2/2 moles C4H10) = 5.6 moles of oxygen required ----------------------------------------
How many moles of hydrogen atoms does 5 moles of propane molecules contain?
Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.
