19
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
This depends on how much hexane was being burned and how much oxygen was present.Because the complete combustion of carbon involves placing two moles of oxygen on one mole of carbon plus the formation of water, you would need 19 moles of diatomic oxygen for every one mole of hexane.1 C6H14 + 19 O2 --> 6 CO2 + 7 H2O
0.41
The oceans contain about 50 times more carbon dioxide (CO2) than the atmosphere and 19 times more than the land biosphere.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
The outcome of the reaction is carbon dioxide and water
Moles = Mass/Molar Mass.Using this equation, we can take 25/(1.0 + 19) and find that it is equal to 1.25 moles.Keep in mind that very few significant figures were used for this example (2), and that if accuracy is to be expected, as many as possible should be used.
4.5
Balance this combustion reaction first! 2C4H10 + 13O2 -> 8CO2 + 10H2O 0.86 moles C4H10 (13 moles O2/2 moles C4H10) = 5.6 moles of oxygen required ----------------------------------------
I mole of LiF is (7 + 19) = 26 g. Thus 32 g is 32/26 moles = 1.23 moles.
19.86 x 1019 carbon atoms (just times it by 6, the number of carbon atoms in one glucose molecule)