How many moles of oxygen are required for the complete combustion of heptane?

Answer 1

The balanced equation for complete combustion of heptane is

C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O.

For each moelcule of heptane, you would need 11 molecules of oxygen gas.

Answer 2

Heptane has the molecule formula: C7H16

When burning things such as alkanes the products are most likely H2O and CO2.

So lets make a reaction equation for this.

C7H16 + O2 --> CO2 + H2O

As you can see the amount of atoms before and after the reaction arrow dont match, just play with the numbers till the number of carbon, hydrogen and oxygen atoms before and after the arrow are the same.

C7H16 + 9 O2 --> 7 CO2 + 8 H2O

This is the reaction, and as you can see, 1 mole of heptane reacts with 9 moles of O2 to form 7 moles of CO2 and 8 moles of H2O.

Answer 3

To determine how many moles of Oxygen is needed for the combustion of 1 mole of Butane, we start with a balanced chemical equation. Butane is C4H10:

2 C4H10 + 13 O2 ---> 8 CO2 + 10 H2O

From the equation, we find that 2 moles of butane require 13 moles of oxygen to combust; therefore, one mole of butane requires 6.5 moles of oxygen.

Answer 4

If the combustion is complete, the equation for the reaction is:

2 C3H10 + 11 O2 -> 6 CO2 + 10 H2O.

Therefore, the moles of oxygen needed will always be 11/2 times the number of moles of propane reacted.

Answer 5

11 moles of oxygen are needed for the complete combustion of heptane.

C7H16 + 11O2 --> 7CO2 + 8H2O

Answer 6

The chemical reaction of this combustion is:
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
Answer: 9,5 moles of oxygen are neede.

Answer 7

The chemical reaction is;
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
For one mole o f hexane 9,5 moles of oxygen are necessary.

Answer 8

11