When the combustion is complete, the balanced equation is:
C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
Balanced equation for the combustion of kerosene:2C12H26 (l) + 37O2(g) ---> 24CO2(g) + 26H2O(g) [AH.rxn = -1.50 x104 kJ]
For the complete combustion reaction, the equation is: C7H16 (l) + 11 O2 (g) => 7 CO2 (g) + 8 H2O (g).
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
Complete combustion of heptane, which has the chemical formula C7H16, produces carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for the combustion of heptane is: C7H16 + 11 O2 → 7 CO2 + 8 H2O
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
no reaction equation
The reaction equation between heptane and potassium permanganate is: C7H16 + 19KMnO4 + 40H2SO4 → 7MnSO4 + 19K2SO4 + 16H2O + 7CO2. This reaction is an oxidation reaction where heptane is converted to carbon dioxide, water, and other byproducts.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
Balanced equation for the combustion of kerosene:2C12H26 (l) + 37O2(g) ---> 24CO2(g) + 26H2O(g) [AH.rxn = -1.50 x104 kJ]
First, calculate the number of moles in 250 kg of heptane by dividing the mass by the molar mass of heptane (C7H16). Then, multiply the number of moles by the heat of combustion to find the total heat released. Finally, convert the result to kilojoules.
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
Well you can see from your equation that each mole of heptane produces 7 moles of Carbon dioxide when burned so 5 moles of heptane produces 5 X 7 moles of carbon dioxide. I'll let you do the maths.