When the combustion is complete, the balanced equation is:
C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
C5h12 + 8o2 -> 5co2 + 6h2o
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
12018750 kJ
Balanced equation for the combustion of kerosene:2C12H26 (l) + 37O2(g) ---> 24CO2(g) + 26H2O(g) [AH.rxn = -1.50 x104 kJ]
For the complete combustion reaction, the equation is: C7H16 (l) + 11 O2 (g) => 7 CO2 (g) + 8 H2O (g).
no reaction equation
There is no reaction
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
This equation is C7H16 + 15 O2 -> 7 CO2 + 8 H2O.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
12018750 kJ
Balanced equation for the combustion of kerosene:2C12H26 (l) + 37O2(g) ---> 24CO2(g) + 26H2O(g) [AH.rxn = -1.50 x104 kJ]
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
Well you can see from your equation that each mole of heptane produces 7 moles of Carbon dioxide when burned so 5 moles of heptane produces 5 X 7 moles of carbon dioxide. I'll let you do the maths.
C7H16 + 1102 ------->8H2O + 7CO2 So 1 molecule of heptane produces 8 molecules of water on combustion and thus 3 molecules produces 24 molecules of water.