This equation is C7H16 + 15 O2 -> 7 CO2 + 8 H2O.
Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.
A complete combustion reaction will produce CO2 and H2O, while an incomplete combustion reaction produces CO and H2O.
A combustion reaction takes place in the presence of O2 (g). The products of a complete combustion reaction are CO2 (g) and H2O (g).
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
Complete combustion is the reaction with oxygen of a material containing at least one of carbon and hydrogen to convert all of the carbon content of the material to carbon dioxide and all of the hydrogen content to water. For methane, CH4 + 2 O2 = CO2 + 2 H2O. But minimum speed range for the CNG vehicle in driving condition should be atleast 50 km per hour for optimum oxygen ratio with methane to achieve complete combustion of CNG
12018750 kJ
When the combustion is complete, the balanced equation is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
For the complete combustion reaction, the equation is: C7H16 (l) + 11 O2 (g) => 7 CO2 (g) + 8 H2O (g).
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
More oxygen is used in a complete combustion.
C7H16 + 1102 ------->8H2O + 7CO2 So 1 molecule of heptane produces 8 molecules of water on combustion and thus 3 molecules produces 24 molecules of water.
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
Heptane has not a pH.
No, heptane is a liquid.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.