12018750 kJ
When the combustion is complete, the balanced equation is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
This equation is C7H16 + 15 O2 -> 7 CO2 + 8 H2O.
When the combustion is complete, the balanced equation is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
For the complete combustion reaction, the equation is: C7H16 (l) + 11 O2 (g) => 7 CO2 (g) + 8 H2O (g).
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
C7H16 + 1102 ------->8H2O + 7CO2 So 1 molecule of heptane produces 8 molecules of water on combustion and thus 3 molecules produces 24 molecules of water.
No, heptane is a liquid.
Heptane has not a pH.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
No, heptane is a liquid at room temperature.
As heptane is lighter than water, it will float.