12018750 kJ
The balanced equation for the combustion of heptane (C7H16) with oxygen (O2) is: C7H16 + 11O2 → 7CO2 + 8H2O
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
Complete combustion of heptane, which has the chemical formula C7H16, produces carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for the combustion of heptane is: C7H16 + 11 O2 → 7 CO2 + 8 H2O
The balanced equation for the combustion of heptane (C7H16) with oxygen (O2) is: C7H16 + 11O2 → 7CO2 + 8H2O
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
For the complete combustion reaction, the equation is: C7H16 (l) + 11 O2 (g) => 7 CO2 (g) + 8 H2O (g).
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
C7H16 + 1102 ------->8H2O + 7CO2 So 1 molecule of heptane produces 8 molecules of water on combustion and thus 3 molecules produces 24 molecules of water.
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
Heptane has not a pH.
There is not a difference in the two products, only the two names. n-heptane is simply medical terminology instead of scientific terminology.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
Yes, heptane is a colorless liquid at room temperature. It is a hydrocarbon compound with the chemical formula C7H16.