27g
how many moles are in 95.0 gram of octane?
The answer is 0,111 moles.
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
85.2 gram LiF sample is equivalent to 3,28 moles.
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
how many moles are in 95.0 gram of octane?
1,99 grams of aluminum is equal to 0,0737 moles.
The answer is 3 moles.
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
The answer is 0,111 moles.
lots
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.