The formula for methane shows that each molecule of it contains 5 atom: 1 carbon atom and 4 hydrogen atoms. The gram molecular mass of methane is 16.04. Therefore, 28 grams of methane contains 28/16.04 moles of methane and 5 times this number, or 8.7, "moles of atoms", to the justified number of significant digits.
28 g = about 1 ounce (0.9877 oz).
There are 28 grams in one ounce. A quarter pound is equivalent to 4 ounces. 28 grams x 4 ounces = 112 grams.
2 pounds = 907.2 grams
no There are 28 grams per ounce. 3 x 28 = 3 x 4 x 7 = 12 x 7 = 84 (greater than 70)
One time the atomic mass of carbon (12 g/mol C) = 12Two times the atomic mass of oxygen (16 g/mol O) = 32Adding up both (totalizing 1*12 and 2*16) gives the molar mass of CO2 = 44 g/mol CO2
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
To determine the number of moles in 5 grams of silicon dioxide (SiO2), you first need to calculate the molar mass of SiO2. The molar mass of SiO2 is 60.08 g/mol. Then, use the formula Moles = Mass / Molar mass to find that there are approximately 0.083 moles in 5 grams of SiO2.
For this you need the atomic (molecular) mass of N2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.25 moles × 28.0 grams = 63.0 grams N2
To calculate the number of moles of nitrogen gas in 35.7 g, you can use the molar mass of nitrogen, which is 28 g/mol. First, divide the given mass by the molar mass to find the number of moles: ( \frac{35.7 , \text{g}}{28 , \text{g/mol}} \approx 1.275 , \text{mol}). Therefore, there are approximately 1.275 moles of nitrogen gas in 35.7 g.
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
There are 28 grams in an ounce of cocaine.
28 grams. One oz. equals 28 grams.
28 grams/1.3 grams = 21.5 (approx)