moles = weight in grams / molecular weight = 56 / 28 = 2 moles
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
To find the number of moles of carbon monoxide in 36.55 g, you need to use its molar mass. The molar mass of carbon monoxide is 28.01 g/mol. Divide the given mass by the molar mass to find the number of moles: 36.55 g / 28.01 g/mol = 1.30 moles of carbon monoxide.
In carbon monoxide (CO), the molar ratio of carbon (C) to oxygen (O) is 1:1. Therefore, in 20 moles of CO, there are 20 moles of carbon. The molar mass of carbon is approximately 12.011 g/mol, so in 20 moles of carbon, there are 20 x 12.011 = 240.22 grams of carbon.
1,4 moles carbon monoxide are produced.
For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.5 grams / 28.0 grams = .161 moles CO
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
To find the number of moles of carbon monoxide in 36.55 g, you need to use its molar mass. The molar mass of carbon monoxide is 28.01 g/mol. Divide the given mass by the molar mass to find the number of moles: 36.55 g / 28.01 g/mol = 1.30 moles of carbon monoxide.
At STP (standard temperature and pressure), 1 mol of any gas occupies 22.4 liters. The molar mass of carbon monoxides is 28.01 g/mol. So, the number of moles in 3.50 grams of carbon monoxide can be calculated. Then, using the ideal gas law, you can determine that 3.50 grams of carbon monoxide at STP would be approximately 0.125 moles and would occupy around 2.8 liters (0.125 moles * 22.4 liters/mol).
In carbon monoxide (CO), the molar ratio of carbon (C) to oxygen (O) is 1:1. Therefore, in 20 moles of CO, there are 20 moles of carbon. The molar mass of carbon is approximately 12.011 g/mol, so in 20 moles of carbon, there are 20 x 12.011 = 240.22 grams of carbon.
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
1,4 moles carbon monoxide are produced.
For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NO=30.0 grams6.64 grams NO / (30.0 grams)= .221 moles NO
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
0,666 moles