For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
6 moles of H2O are needed to balance the reaction. Mg3N2 + 6H2O → 3Mg(OH)2 + 2NH3. Each mole of Mg3N2 reacts with 3 moles of H2O.
To determine the number of moles of carbon dioxide produced when hexane is burned, we need to consider the balanced chemical equation for the combustion of hexane, which is C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O. From the balanced equation, we can see that for every mole of hexane burned, 6 moles of carbon dioxide are produced. Therefore, if 84.4 moles of hexane is burned, 6 * 84.4 = 506.4 moles of carbon dioxide would be produced.
12 moles
12 g NF3 equals 0,17 moles.
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
6 moles of H2O are needed to balance the reaction. Mg3N2 + 6H2O → 3Mg(OH)2 + 2NH3. Each mole of Mg3N2 reacts with 3 moles of H2O.
To determine the number of moles of carbon dioxide produced when hexane is burned, we need to consider the balanced chemical equation for the combustion of hexane, which is C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O. From the balanced equation, we can see that for every mole of hexane burned, 6 moles of carbon dioxide are produced. Therefore, if 84.4 moles of hexane is burned, 6 * 84.4 = 506.4 moles of carbon dioxide would be produced.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
12 g of potassium is equivalent to 0,307 moles.
12 g NF3 equals 0,17 moles.
12 moles
Balanced equation. C + O2 -> CO2 22.2 grams carbon (1 mole C/12.01 grams)(1 mole CO2/1 mole C) = 1.85 moles carbon dioxide produced -------------------------------------------------
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
These reagents doesn't react.