Mass of 4 mole CO2 , this is 4 * (12 + 2*16) = 176 grams
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
For this reaction, the stoichiometry indicates that 4 moles of CO2 are produced for every 2 moles of C2H2 reacted. The molar mass of CO2 is approximately 44 g/mol. Therefore, you can calculate the mass of CO2 produced by converting the moles of CO2 into grams.
To calculate the number of moles of oxygen in the reaction vessel, you need to know the amount of oxygen in grams and its molar mass. Then divide the mass of oxygen by its molar mass to obtain the number of moles. The formula to calculate the number of moles is: moles = mass / molar mass.
To calculate the grams of SnF2 produced, you need to first determine the moles of HF using the molar mass of HF. Then use the mole ratio between HF and SnF2 from the balanced chemical equation to find the moles of SnF2 produced. Finally, convert the moles of SnF2 to grams using the molar mass of SnF2.
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
To determine the mass of ammonia produced, you first need to calculate the moles of hydrogen gas present. Then, you can use the stoichiometry of the balanced chemical equation for the reaction between hydrogen and nitrogen to find the moles of ammonia produced. Finally, using the molar mass of ammonia, you can convert moles to grams to find the mass of ammonia produced.
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
To find the grams of carbon dioxide produced, first determine the moles of 1-heptanol using its molar mass. Then, use the balanced combustion equation of 1-heptanol to find the moles of CO2 produced. Finally, convert moles of CO2 to grams using its molar mass.
To determine the moles of excess sulfuric acid left over after the reaction is complete, you need to compare the stoichiometry of the reactants. In this case, 2 moles of NH3 reacts with 1 mole of H2SO4. If you know the initial moles of NH3 and H2SO4 used in the reaction, you can calculate which one is in excess and how many moles of the excess reactant are left over.
To find the mass of water produced, we first need to determine the molar ratio of water to nitrous oxide in the reaction. Once we have the mole ratio, we can use it to calculate the moles of water produced from the moles of nitrous oxide. Finally, we can convert the moles of water to grams using the molar mass of water.
To calculate the moles of gas produced, first find the moles of Mg reacting by dividing the mass by the molar mass of Mg. Next, determine the mole ratio of Mg to gas produced from the balanced chemical equation of the reaction. Finally, multiply the moles of Mg by the mole ratio to find the moles of gas produced.
The balanced chemical equation for this reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that 1 mole of AgNO3 produces 1 mole of AgCl. Since the molar mass of AgNO3 is 169.87 g/mol, 83.0 g of AgNO3 is equivalent to 0.488 moles. Therefore, 0.488 moles of AgCl will be produced.
For this reaction, the stoichiometry indicates that 4 moles of CO2 are produced for every 2 moles of C2H2 reacted. The molar mass of CO2 is approximately 44 g/mol. Therefore, you can calculate the mass of CO2 produced by converting the moles of CO2 into grams.
To find the mass of Au produced, first calculate the molar mass of Au2S3 (gold (III) sulfide) and Au. Then use the stoichiometry of the balanced chemical equation of the reaction between Au2S3 and H2 to determine the moles of Au produced. Finally, multiply the moles of Au produced by the molar mass of Au to find the mass.
To calculate the mass of water produced when 32 grams of copper is consumed, we need to use the stoichiometry of the reaction. Given the balanced chemical equation for the reaction of copper with water, we can determine the moles of copper reacting and then use the mole ratio to find the moles of water produced. Finally, using the molar mass of water, we can calculate the mass of water produced.