12 moles
16 grams of oxygen how many moles is 0,5 moles.
moles of what?
2 moles of Ca and 4 moles of OH
To convert 1349 grams of Na3PO4 (sodium phosphate) to miles, you first need to determine the context of the question, as grams and miles measure different things. If you're asking about the distance related to a specific quantity or scenario involving Na3PO4, please clarify. Otherwise, there is no direct conversion between grams of a substance and miles.
55.8 moles
There are 0.75 moles of sodium ions present in 2.50 L of 0.300 M Na3PO4. Each formula unit of Na3PO4 has 3 sodium ions. So, for every mole of Na3PO4, there are 3 moles of sodium ions. Calculating the moles of sodium ions: 2.5 L * 0.300 mol/L * 3 mol Na+ / 1 mol Na3PO4 = 0.75 moles of Na+.
There are 3 moles of sodium represented in one mole of sodium phosphate (Na3PO4). This is because the subscript 3 in Na3PO4 indicates that there are 3 sodium ions for every molecule of sodium phosphate.
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
2,196.10-12 pmol of Na3PO4. (p is pico)
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
To calculate the number of moles in 10 grams of sodium phosphate (Na3PO4), we first need to determine the molar mass of Na3PO4, which is approximately 164.0 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, for 10 grams of sodium phosphate, there would be approximately 0.061 moles present.
Ba3(PO4) is an incorrect formula. Barium phosphate has the formula 'Ba3(PO4)2 '. So write down the BALANCED reaction eq'n. 2Na3PO4 + 3Ba(NO3)2 = 6NaNO3 + Ba3(PO4)2 The molar ratios are 2:3 :: 6:1 We have 3.25 mol(Na3PO4) equivalent to '2' & 7.03 mol(Ba(NO3)2 ) equivalent to '3' We now must find the limiting reactant. So 3..25 / 2 = 1.625 & 7.03/3 = 2.34333.... We only need 1.625 moles(Na3PO4) to react with 7.03 moles (Ba(NO3)2). So at 3.25 moles the sodium phosphate is in excess. Therefore 7.03 moles barium nitrate is the limiting reactant. By equivalence 3:1 ;; 7.03 : x Hence x /1 = 7.03 / 3 x = 7.03 x 1 / 3 x = 2.34333... moles(Ba(NO3)2) is produced.
Many phosphates are known; as an example Na3PO4 has a trigonal crystalline structure.
The chemical formula for sodium phosphate is Na3PO4, which exists as a solid white powder at room temperature
As given 'Na3PO4' it is impossible to tell, because you also need the mass of sodium phosphate. Then use the eq'n moles = mass(g) / Mr From the Periodic Table we can calculate the Mr. Naa x 3 = 23 x 3 = 69 P x 1 = 31 x 1 = 31 O x 4 = 16 x 4 = 64 69 + 31 + 64 = 164 164 is the Relative molecular mass (Mr) of sodium phosphate. However, mass(g) = 1 mole X 164(Mr) mass of 1 mole = 164 grams. Similarly mass(g) = 2 moles X 164(Mr) mass of 2 moles = 328 grams. et seq., So you need to know the mass in order to calculate the moles.
Of course 6 moles.
16 grams of oxygen how many moles is 0,5 moles.