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What is the ratio of moles of CuSO4 to moles of water?
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
How will you convert the masses of anhydrous CuSO4 and water to moles?
To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
How many moles of N are in 0.161g of N2O?
There are 0.003659 N2O moles. So there are o.007318 moles of N.
How many moles of O are in one mole of copper II sulphate?
Well, honey, in one mole of copper II sulfate, there are 4 moles of oxygen atoms. So, if you're asking about moles of oxygen molecules (O₂), then the answer is 8 moles. But if you're talking about individual oxygen atoms, then it's 4 moles. Either way, you've got a whole lotta oxygen hanging out with that copper II sulfate.
What is the ratio of moles of CuSO4 to moles of water?
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
How many moles are in one gram of CuSO4?
The answer is 159,62 g for the anhydrous salt.
What is the ratio of moles of CuSO4 to moles of NaOH?
This ratio is 1:2.
How many moles are in 44.78 g of cupric sulfate?
CuSO4 (cupric sulfate) has a molecular weight of 159.602g/mol Cu=63.546 S =32.06 O = 15.999 x 4 =63.996 Add the atomic weights of the elements in cupric sulfate. This is 159.602 grams/mol. Now divide the number of grams( 44.78) by the molecular weight of cupric sulfate (159.602). 44.78 g CuSO4/159.602 g/mol CuSO4= .2805 mol(moles) of cupric sulfate. The answer is 0.2805
How many moles of solute particles are present in 1mL exact of aqueous 0.990 M CuSO4?
M = moles solute/ Liters solution 1 mL= 0.001 L 0.990M x 0.001 L =9.9 x 10^-4 moles CuSO4 9.9 x 10^-4 *2 = 0.00198 solute particles *When you dissolve 1 mole CuSO4 in water, it dissolves into 1 mol of Cu+ ions and 1mol of SO4- ions, which gives you twice as many moles of solute particles- which is why you multiply 9.9 x 10^-4 by 2. Hope this helps
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
Do a 5m cuso4 and 5m cuso4 5 h2o contain the same quantities of cuso4?
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
How many atoms and elements does CuSO4 have?
One molecule has 6 individual atoms. If the number you are looking for is much larger than that you need to know how many grams or moles of CuSO4 you are supposed to calculate.
How will you convert the masses of anhydrous CuSO4 and water to moles?
To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
How many grams of metallic copper can be obtained when 54.0 g of Al react with 319 g of CuSO4?
To solve this problem, start by writing a balanced chemical equation for the reaction between Al and CuSO4. The molar ratio from the balanced equation indicates that 1 mole of Al reacts with 3 moles of CuSO4 to form 3 moles of Cu. Calculate the moles of Al and CuSO4 in the given masses, determine the limiting reactant, and use stoichiometry to find the mass of metallic Cu produced.
How many moles of plumbous nitrate are required to react with 0.25 moles of cupric sulfate?
The balanced chemical equation for the reaction between plumbous nitrate and cupric sulfate is: Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2 From the equation, we can see that 1 mole of plumbous nitrate (Pb(NO3)2) reacts with 1 mole of cupric sulfate (CuSO4). Therefore, 0.25 moles of cupric sulfate will require 0.25 moles of plumbous nitrate for complete reaction.
