CuSO4 (cupric sulfate) has a molecular weight of 159.602g/mol Cu=63.546 S =32.06 O = 15.999 x 4 =63.996 Add the atomic weights of the elements in cupric sulfate. This is 159.602 grams/mol. Now divide the number of grams( 44.78) by the molecular weight of cupric sulfate (159.602). 44.78 g CuSO4/159.602 g/mol CuSO4= .2805 mol(moles) of cupric sulfate. The answer is 0.2805
To find the number of moles, you need to divide the given mass (44.78g) by the molar mass of cupric sulfate. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. Therefore, 44.78g of cupric sulfate is approximately 0.28 moles.
To find the number of moles of cupric sulfate, we need to divide the given mass by its molar mass. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. 44.78 g / 159.61 g/mol ≈ 0.281 moles Therefore, Yonas has approximately 0.281 moles of cupric sulfate.
The balanced chemical equation for the reaction between plumbous nitrate and cupric sulfate is: Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2 From the equation, we can see that 1 mole of plumbous nitrate (Pb(NO3)2) reacts with 1 mole of cupric sulfate (CuSO4). Therefore, 0.25 moles of cupric sulfate will require 0.25 moles of plumbous nitrate for complete reaction.
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
To find the number of moles, you need to divide the given mass (44.78g) by the molar mass of cupric sulfate. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. Therefore, 44.78g of cupric sulfate is approximately 0.28 moles.
To find the number of moles of cupric sulfate, we need to divide the given mass by its molar mass. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. 44.78 g / 159.61 g/mol ≈ 0.281 moles Therefore, Yonas has approximately 0.281 moles of cupric sulfate.
Cupric sulfate is CuSO4 which has a molar mass of 159.6g/mol. Thus 44.78 g x 1 mol/159.6 g = 0.2806 moles (to 4 significant figures).
The balanced chemical equation for the reaction between plumbous nitrate and cupric sulfate is: Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2 From the equation, we can see that 1 mole of plumbous nitrate (Pb(NO3)2) reacts with 1 mole of cupric sulfate (CuSO4). Therefore, 0.25 moles of cupric sulfate will require 0.25 moles of plumbous nitrate for complete reaction.
Cupric sulfate, also known as copper(II) sulfate, has the chemical formula CuSO4. It contains one copper atom (Cu), one sulfur atom (S), and four oxygen atoms (O) in one molecule. So, there are a total of six atoms in one molecule of cupric sulfate.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
When hydrated copper sulfate is heated, it loses its water molecules to form anhydrous copper sulfate. Since the molar ratio between the two forms is 1:1, if 6.4 moles of hydrated copper sulfate is heated, 6.4 moles of anhydrous copper sulfate will be produced.
5,7 moles (SO4)3-.
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.