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How many moles of O in CuSO4?
moles of what?
How will you convert the masses of anhydrous CuSO4 and water to moles?
To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
The number of water molecules attched to CuSO4 IS?
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
For the reaction 2H2 plus O2 equals 2H2O how much water is produced when 2.5 moles of hydrogen react completely How do you do the problem?
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
What is the ratio of moles of CuSO4 to moles of NaOH?
This ratio is 1:2.
How many moles of O in CuSO4?
moles of what?
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
How many moles of solute particles are present in 1mL exact of aqueous 0.990 M CuSO4?
M = moles solute/ Liters solution 1 mL= 0.001 L 0.990M x 0.001 L =9.9 x 10^-4 moles CuSO4 9.9 x 10^-4 *2 = 0.00198 solute particles *When you dissolve 1 mole CuSO4 in water, it dissolves into 1 mol of Cu+ ions and 1mol of SO4- ions, which gives you twice as many moles of solute particles- which is why you multiply 9.9 x 10^-4 by 2. Hope this helps
Do a 5m cuso4 and 5m cuso4 5 h2o contain the same quantities of cuso4?
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
How many grams of metallic copper can be obtained when 54.0 g of Al react with 319 g of CuSO4?
To solve this problem, start by writing a balanced chemical equation for the reaction between Al and CuSO4. The molar ratio from the balanced equation indicates that 1 mole of Al reacts with 3 moles of CuSO4 to form 3 moles of Cu. Calculate the moles of Al and CuSO4 in the given masses, determine the limiting reactant, and use stoichiometry to find the mass of metallic Cu produced.
How many moles of sulfur are contained in a sample of CuSO4 that also contains 3.50 x 1023 oxygen atoms?
To find the number of moles of sulfur in the sample of CuSO4, we first need to determine the molar ratio of sulfur to oxygen in CuSO4. The formula for CuSO4 shows that there is one sulfur atom for every four oxygen atoms. Since 3.50 x 10^23 oxygen atoms are present, there would be 3.50 x 10^23 / 4 = 8.75 x 10^22 sulfur atoms. This is equivalent to 8.75 x 10^22 moles of sulfur.
What equation is sulphuric acid mixed with copper oxide?
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).
How many moles are in 44.78 g of cupric sulfate?
CuSO4 (cupric sulfate) has a molecular weight of 159.602g/mol Cu=63.546 S =32.06 O = 15.999 x 4 =63.996 Add the atomic weights of the elements in cupric sulfate. This is 159.602 grams/mol. Now divide the number of grams( 44.78) by the molecular weight of cupric sulfate (159.602). 44.78 g CuSO4/159.602 g/mol CuSO4= .2805 mol(moles) of cupric sulfate. The answer is 0.2805
How many moles are in one gram of CuSO4?
The answer is 159,62 g for the anhydrous salt.
The relative number of moles of hydrogen to moles of oxygen that react to form water represents what?
The ratio H/O is 2.
