M = moles solute/ Liters solution
1 mL= 0.001 L
0.990M x 0.001 L =9.9 x 10^-4 moles CuSO4
9.9 x 10^-4 *2 = 0.00198 solute particles
*When you dissolve 1 mole CuSO4 in water, it dissolves into 1 mol of Cu+ ions and 1mol of SO4- ions, which gives you twice as many moles of solute particles- which is why you multiply 9.9 x 10^-4 by 2.
Hope this helps
yes
You get a precipitate that is a sky blue and clear solution.
Zn(SO4)+Cu
In aqueous solution blue precipitates of Copper (II) hydroxide are formed, CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4
A non-electrolyte solution is one in which there are no charged particles dissolved in the solution.For example:Sodium chloride will form an electrolyte solution in water because the sodium ions and chloride ions dissociate when dissolved in water.NaCl(s) + H2O --> Na(aq)++ Cl(aq)-Sucrose will form a non-electrolyte solution in water because no charged particles will dissociate in the solution.C12H22O11(s) + H2O --> C12H22O11(aq)The sucrose is not chemically changed, it's just dissolved in the water, forming a sucrose solution.*(aq) means aqueous (dissolved in water)
BLUE
yes
The solution of CuSO4 is blue.The solution of FeSO4 is green.
boil it thats it
You get a sodium sulfate deposit.
It depends on the copper charge.Cu2SO4(aq) or CuSO4(aq)
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
You get a precipitate that is a sky blue and clear solution.
In aqueous solution blue precipitates of Copper (II) hydroxide are formed, CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4
A non-electrolyte solution is one in which there are no charged particles dissolved in the solution.For example:Sodium chloride will form an electrolyte solution in water because the sodium ions and chloride ions dissociate when dissolved in water.NaCl(s) + H2O --> Na(aq)++ Cl(aq)-Sucrose will form a non-electrolyte solution in water because no charged particles will dissociate in the solution.C12H22O11(s) + H2O --> C12H22O11(aq)The sucrose is not chemically changed, it's just dissolved in the water, forming a sucrose solution.*(aq) means aqueous (dissolved in water)
Zn(SO4)+Cu
The equation for this reaction is CuO (s) + H2SO4 (aq) -> CuSO4 (aq) + H2O (l).