The solution of CuSO4 is blue.
The solution of FeSO4 is green.
In an aqueous solution the solvent is water.
As gaseous ammonia with solid coppersulfate: 2NH3(g) + CuSO4(s) --> Cu(NH3)2SO4(s) With water: [Cu(NH3)2]2+ complex-ions with SO42- ions in aquous solution (deep blue color)
bekar ka question
Anhydrous Copper Sulfate will be white. The original crystals (CuSO4 pentahydrate) will be blue.
A typical aqueous solution containing phenolpthalein is colorless within the pH range 2 - 6.
The aqueous solution of ferrous sulfate, FeSO4, is light green on heating. It changes to yellow then brown due to formation of ferric sulfate.
Ag+ is colorless. (:
In an aqueous solution the solvent is water.
iron(Fe) being more reactive than Copper(Cu) displaces Cu from copper sulphate (CuSO4). Thus, the following equation is derived:Fe + CuSO4 -----> FeSO4 + CuOBSERVATIONS-1. reddish-brown deposit on the surface of nail2. surface of the nail is found corroded3. the blue solution turns light green
orange-red
It creates a clear aqueous solution with a blue tint.
Usually chromium with an oxidation state of +6 MnO4- will also impart a purple color in a solution
MnO4- (aq) the permanganate ion
The color of the heptahydrate FeSO4. 7 H2O is green. After thermal dehydration the monohydrate FeSO4.H2O is formed and this is colorless.
A displacement reaction takes place. Iron being a more reactive element than copper displaces copper from its compound. Ferrous Sulphate which is green in color and copper a reddish brown element are formed. So, blue color of copper sulphate fades away and the solution becomes light green. Copper is deposited on the grayish iron filings.
Simple phenol (Carbolic acid) is almost colourless in aqueous solution but Naphthols forms pinkish or purple solutions.
Blue is the solution's color When blue CuSO4.5H2O (copper(II) sulfate pentahydrate) is dissolved, the solution turns blue. When white CuSO4 (anhydrous copper(II) sulfate) is dissolved, the solution turns also blue.