To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
1 mol of MgSO4.7H2O has 246,47 g.
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
moles of what?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
This depends on: - if it is an anhydrous or hydrated salt - if it is a salt of Cu(I) or Cu(II) For CuSO4(anh.) the answer is 0,00364 moles.
1 mol of MgSO4.7H2O has 246,47 g.
The answer is 159,62 g for the anhydrous salt.
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
moles of what?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
This ratio is 1:2.
Hello, Very simply, if the molar ratio is 1:1 mole, then divide the molecular weight of the anhydrous material by the hydrated one, then multiply the result by 8.753 g. Solution: NiSO4 anhydrous molecular weight is 154.75 g/mol (anhydrous) NiSO4·7H2O molecular weight is 280.86 g/mol (heptahydrate) So: 154.75/280.86 = 0.55098 The grams quantity produced from 8.753 heptahydrate is (0.55098*8.753) = 4.823 grams anhydrous NiSO4 anhydrous Best wishes AD
If you know moles of each use their molar masses to convert to mass.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
To solve this problem, start by writing a balanced chemical equation for the reaction between Al and CuSO4. The molar ratio from the balanced equation indicates that 1 mole of Al reacts with 3 moles of CuSO4 to form 3 moles of Cu. Calculate the moles of Al and CuSO4 in the given masses, determine the limiting reactant, and use stoichiometry to find the mass of metallic Cu produced.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.