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To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
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How will you convert the masses of anhydrous MgSO4 and water to moles?
1 mol of MgSO4.7H2O has 246,47 g.
What is the ratio of moles of CuSO4 to moles of water?
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
How many moles of O in CuSO4?
moles of what?
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
How many formula units are in 0.75 moles of AlCl3?
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
How do you convert 0.570 grams of copper sulphate to moles?
This depends on: - if it is an anhydrous or hydrated salt - if it is a salt of Cu(I) or Cu(II) For CuSO4(anh.) the answer is 0,00364 moles.
How will you convert the masses of anhydrous MgSO4 and water to moles?
1 mol of MgSO4.7H2O has 246,47 g.
How many moles are in one gram of CuSO4?
The answer is 159,62 g for the anhydrous salt.
What is the ratio of moles of CuSO4 to moles of water?
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
How many moles of O in CuSO4?
moles of what?
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
How many grams of anhydrous nickel 2 sulfate is produced from 8.753 grams of heptahydrate?
Hello, Very simply, if the molar ratio is 1:1 mole, then divide the molecular weight of the anhydrous material by the hydrated one, then multiply the result by 8.753 g. Solution: NiSO4 anhydrous molecular weight is 154.75 g/mol (anhydrous) NiSO4·7H2O molecular weight is 280.86 g/mol (heptahydrate) So: 154.75/280.86 = 0.55098 The grams quantity produced from 8.753 heptahydrate is (0.55098*8.753) = 4.823 grams anhydrous NiSO4 anhydrous Best wishes AD
What is the ratio of moles of CuSO4 to moles of NaOH?
This ratio is 1:2.
How do you calculate the masses of carbon dioxide hydrogen and oxyen at STP?
If you know moles of each use their molar masses to convert to mass.
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
How many grams of metallic copper can be obtained when 54.0 g of Al react with 319 g of CuSO4?
To solve this problem, start by writing a balanced chemical equation for the reaction between Al and CuSO4. The molar ratio from the balanced equation indicates that 1 mole of Al reacts with 3 moles of CuSO4 to form 3 moles of Cu. Calculate the moles of Al and CuSO4 in the given masses, determine the limiting reactant, and use stoichiometry to find the mass of metallic Cu produced.
Do a 5m cuso4 and 5m cuso4 5 h2o contain the same quantities of cuso4?
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
