0
What else can I help you with?
How many formula units of salt make up 10 moles?
10 formula units
How many moles are equivalent to 3.6x1024 formula units of MgBr2?
The answer is 5,978 moles.
How many formula units are in 5.38 moles of potassium sulfate?
The answer is 32,4.10e23.
How many moles of CaCl2 contains 1.26 times 10 24 formula units CaCI2?
The answer is 2,09 moles.
How many formula units of salt take up 10 moles?
A formula unit of salt, such as sodium chloride (NaCl), represents one mole of the compound. Therefore, if you have 10 moles of salt, you have 10 formula units of NaCl. In other words, for every mole of salt, there is one corresponding formula unit. Thus, 10 moles of salt correspond to 10 formula units.
How many formula units of salt make up 10 moles?
10 formula units
How many moles are equivalent to 3.6x1024 formula units of MgBr2?
The answer is 5,978 moles.
How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
How many formula units of sodium acetate are in 0.87 moles of sodium acetate?
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
How many formula units are in 5.38 moles of potassium sulfate?
The answer is 32,4.10e23.
How many moles of CaCl2 are in 2.00 1024 formula units?
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
How many moles of AlCl3 are produced from 0.30 mole of Cl2 Show the work?
Balanced equation: 2Al + 3Cl2 -> 2AlCl3For every 3 moles of Cl2, 2 moles of AlCl3 is produced (Using the numbers in front of the compounds)Now set up a proportion: 3/2 = 0.30/?Cross Multiply: (2 X 0.30) / 3 = 0.20.2 moles of AlCl3 will be produced.
How many formula units of LiCl are equal to .648 moles?
42.394 grams.
How many moles of CaCl2 contains 1.26 times 10 24 formula units CaCI2?
The answer is 2,09 moles.
How many chloride ions are present in 65.5 mL of 0.210 M AlCl3 solution?
In 1 mol of AlCl3, there are 3 chloride ions. First calculate the moles of AlCl3 in the solution: 65.5 mL is 0.0655 L. Multiply 0.0655 L by 0.210 mol/L to get the moles of AlCl3. Finally, multiply this by 3 to find the number of chloride ions in the solution.
How many moles are there in 2.3 x 1023 formula units of NaCl?
(2.3 x 10^23) / (6.02 x 10^23) =0.38 moles
How many formula units are there in 2.45 moles potassium chloride?
To determine the number of formula units in 2.45 moles of potassium chloride, you first need to find the molar mass of KCl, which is approximately 74.55 g/mol. Then, divide the number of moles by the molar mass to get the number of formula units. Therefore, 2.45 moles of KCl is equivalent to about 163 formula units.
