The answer is 2,09 moles.
There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.
2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
The formula for magnesium oxide is MgO, showing that each formula unit of magnesium oxide contains one mole of magnesium ions. Therefore, if there is ample oxygen available, 4 moles of magnesium will form 4 moles of magnesium oxide.
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
mom
The answer is 3,33 moles.
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
The chemical formula for calcium chloride is CaCl2, and its formula weight is 110.99. The formula shows that each formula weight of calcium chloride contains one mole of calcium ions. In 166.5 grams, there are 166.5/110.99 or 1.500 formula weights of calcium chloride and the same number of moles of calcium ions.
2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
0.89 moles of CaCl2 is equal to 98.8g.
The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================
This depends of the concentration of CaCl2 in this solution.