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Oh, dude, let me break it down for you. So, 1 mole of CaCl2 contains 6.022 x 10^23 formula units, right? And you've got 1.26 x 10^24 formula units of CaCl2. So, you just divide 1.26 x 10^24 by 6.022 x 10^23 to get the number of moles. Easy peasy, lemon squeezy!
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
To find the molarity of Cl in the solution, first calculate the number of moles of CaCl2 using its molar mass. Then, since each formula unit of CaCl2 contains 2 moles of Cl, multiply the moles of CaCl2 by 2 to get moles of Cl. Finally, divide moles of Cl by the volume of the solution in liters to find the molarity.
To find the number of moles of CaCl2, first calculate the molar mass of CaCl2: Ca: 40.08 g/mol Cl: 35.45 g/mol (x2 since there are two Cl atoms) Total molar mass: 40.08 + 35.45(2) = 110.98 g/mol Next, calculate the number of moles: 2.41 x 10^24 formula units / Avogadro's number (6.022 x 10^23) = 4 moles of CaCl2.
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
Oh, dude, let me break it down for you. So, 1 mole of CaCl2 contains 6.022 x 10^23 formula units, right? And you've got 1.26 x 10^24 formula units of CaCl2. So, you just divide 1.26 x 10^24 by 6.022 x 10^23 to get the number of moles. Easy peasy, lemon squeezy!
There are 3.01 x 10^24 formula units of CaCl2 in 2.50 moles. This can be calculated using Avogadro's number (6.022 x 10^23) and the formula units present in one mole of CaCl2 (3).
The answer is 2,09 moles.
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
To find the molarity of Cl in the solution, first calculate the number of moles of CaCl2 using its molar mass. Then, since each formula unit of CaCl2 contains 2 moles of Cl, multiply the moles of CaCl2 by 2 to get moles of Cl. Finally, divide moles of Cl by the volume of the solution in liters to find the molarity.
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
To find the mass of CaCl2 needed, you need to use the formula: Mass = molarity × volume × molar mass. First, calculate the number of moles of CaCl2 using the molarity and volume. Then, multiply the moles by the molar mass of CaCl2 (110.98 g/mol) to find the mass needed. A 1.56 M solution means it contains 1.56 moles of CaCl2 in 1 liter of solution.
To find the number of moles of CaCl2, first calculate the molar mass of CaCl2: Ca: 40.08 g/mol Cl: 35.45 g/mol (x2 since there are two Cl atoms) Total molar mass: 40.08 + 35.45(2) = 110.98 g/mol Next, calculate the number of moles: 2.41 x 10^24 formula units / Avogadro's number (6.022 x 10^23) = 4 moles of CaCl2.
There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.
To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.