The answer is 3,33 moles.
To find the number of moles, first determine the number of formula units in one mole of NaCl. One mole of NaCl contains Avogadro's number (6.022 x 10^23) of formula units. Therefore, 4.816 x 10^24 formula units of NaCl is equal to 8 moles.
In one mole of CaCl2, there are 2 moles of chloride ions since there are 2 chloride ions for every 1 CaCl2 molecule. Therefore, there are 2 * 6.022 x 10^23 = 1.2044 x 10^24 chloride ions in one mole of CaCl2.
The chemical formula for water is H2O; therefore each formula unit has three atoms. Avogadro's number is defined as the number of formula units per mole. Therefore, the answer to the stated question is 3 X 6.022 X 1023 = about 1.8066 X 1024 atoms. (If the value "3" is not considered exact, only one significant digit is justified; in that instance, the answer should be written. as 2 X 1024.
The formula shows that there is one atoms of iron in each formula unit of FeCl3, and by definition the number of molecules or formula units in a mole is Avogadro's Number. Therefore, 5.33 moles contains 5.33 X Avogadro's Number of atoms, which is 3.21 X 1024 atoms, to the justified number of significant digits.
To determine the number of molecules in a sample of LiCl, we need to first calculate the number of moles using the molar mass of LiCl (42.39 g/mol). Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, there are approximately (127.17 \text{ g} / 42.39 \text{ g/mol} \approx 3 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} ≈ 1.8 \times 10^{24}) molecules of LiCl in 127.17 g.
Oh, dude, let me break it down for you. So, 1 mole of CaCl2 contains 6.022 x 10^23 formula units, right? And you've got 1.26 x 10^24 formula units of CaCl2. So, you just divide 1.26 x 10^24 by 6.022 x 10^23 to get the number of moles. Easy peasy, lemon squeezy!
To find the number of moles of CaCl2, first calculate the molar mass of CaCl2: Ca: 40.08 g/mol Cl: 35.45 g/mol (x2 since there are two Cl atoms) Total molar mass: 40.08 + 35.45(2) = 110.98 g/mol Next, calculate the number of moles: 2.41 x 10^24 formula units / Avogadro's number (6.022 x 10^23) = 4 moles of CaCl2.
4.5 moles NaCl = 4.5000000000001 formula units NaCl *******************2nd Opinion************* 4.5 moles of NaCl would contain 4.5 x (6.02 x 1023) formula units. = 2.7 x 1024 formula units
9.54*1024
To find the number of moles, first determine the number of formula units in one mole of NaCl. One mole of NaCl contains Avogadro's number (6.022 x 10^23) of formula units. Therefore, 4.816 x 10^24 formula units of NaCl is equal to 8 moles.
In one mole of CaCl2, there are 2 moles of chloride ions since there are 2 chloride ions for every 1 CaCl2 molecule. Therefore, there are 2 * 6.022 x 10^23 = 1.2044 x 10^24 chloride ions in one mole of CaCl2.
Vanadium does not have moles but rather formula units. The formula unit for vanadium is a single atom. Therefore, the number of formula units in any number of atoms is equal to the number of atoms divided by Avogadro's Number, in this instance 7.17 X 10-3 formula units.
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
The equivalent is two moles.
The answer is 15,2 moles.
Sodium chloride is an ionic crystalline salt, and does not form molecules. One unit of sodium chloride is called a functional unit. It is the lowest whole number ratio of ions represented in an ionic compound. 1 mole = 6.022 x 1023 formula units of NaCl 3 moles NaCl x 6.022 x 1023 formula units/mole = 1.8 x 1024 formula units of NaCl
The gram formula unit mass of sodium chloride is 58.443, and every gram formula unit mass contains Avogadro's Number, 6.022 X 1023 formula units. Therefore, the mass sought is 58.443 X (4.59 X 1024)/(6.022 X 1023) or 445 grams, to the justified number of significant digits.