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How many molecules are present in 936 g of glucose?
To find the number of molecules present in 936 g of glucose, you would first calculate the number of moles of glucose using its molecular weight. Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many atoms are in 1.54 moles of Bromine Br?
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
How many moles are there in 1.2 x 1024?
The equivalent is two moles.
How many carbon dioxide molecules are needed to produce 3 molecules of glucose?
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
How many moles of H20 are in 3.6 x 1024 molecules of H20?
divide this number by avagadros number to get moles. (5.16x1024)/(6.02x1023)=8.57mol of H2O as there are 3 atoms in each molecule there are 3x8.57=25.7 moles of atoms.
How many moles of glucose are there in 2.4088 x 1024 molecules of glucose?
To find the number of moles, use Avogadro's number: 1 mole = 6.022 x 10^23 molecules. Divide the number of molecules given by Avogadro's number to get the number of moles. In this case, 2.4088 x 10^24 molecules ÷ 6.022 x 10^23 molecules/mole ≈ 4 moles of glucose.
How many molecules are in 2.0 moles of propane?
1.204 x 1024
How many molecules are present in 936 g of glucose?
To find the number of molecules present in 936 g of glucose, you would first calculate the number of moles of glucose using its molecular weight. Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many moles are in 2.408 x 1024 molecules of CO2?
To find the number of moles in 2.408 x 10^24 molecules of CO2, you can use Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole. Therefore, 2.408 x 10^24 molecules / 6.022 x 10^23 molecules per mole = about 4 moles of CO2.
How many atoms are in 1.54 moles of Bromine Br?
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
How many moles are there in 1.2 x 1024?
The equivalent is two moles.
How many moles are contained in 4.65 x 1024 molecules of CO?
1 mole contains 6.022 x 1023 molecules. number of moles of CO= (4.65 x 1024) / (6.022 x 1023) = 7.72 mol The identity of the molecule does not change the answer.
How many moles of trifluoromethanoic acid (CHF3O3S) are present in 9.0345 1024 molecules of (CHF3O3S)?
To find the number of moles in 9.0345 x 10^24 molecules of trifluoromethanoic acid (CHF3O3S), you can divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Number of moles = 9.0345 x 10^24 molecules / 6.022 x 10^23 molecules/mol = 15 moles.
How many carbon dioxide molecules are needed to produce 3 molecules of glucose?
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
How many moles of H20 are in 3.6 x 1024 molecules of H20?
divide this number by avagadros number to get moles. (5.16x1024)/(6.02x1023)=8.57mol of H2O as there are 3 atoms in each molecule there are 3x8.57=25.7 moles of atoms.
How many moles of krypton do you have if you have 9.15 x 1024 atoms of krypton?
The answer is 15,2 moles.
How many molecules are present in 936 g of glucose (c6h12o6)?
To find the number of molecules in 936 g of glucose (C₆H₁₂O₆), first calculate the molar mass of glucose, which is approximately 180.18 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, 936 g of glucose corresponds to about 5.19 moles. Finally, multiplying the moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) gives roughly (3.12 \times 10^{24}) molecules of glucose.
