1.204 x 1024
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means that 5 moles of oxygen are required to completely combust 1 mole of propane. Therefore, 20 moles of oxygen would be produced from the complete combustion of 4 moles of propane.
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
5.8
For every mole of C3H8 that reacts, 4 moles of water are formed. Therefore, 5.0 moles of C3H8 will form 5.0 x 4 = 20 moles of water. To convert moles to molecules, you would then multiply by Avogadro's number (6.022 x 10^23 molecules/mol). So, 20 moles of water would equal 20 x 6.022 x 10^23 = 1.2044 x 10^25 molecules of water.
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
Propane has a density of about 4.24 pounds per gallon. Therefore, to convert 20 pounds of propane to gallons, you would divide 20 by 4.24, which equals approximately 4.72 gallons of propane.
20 moles
20 LBS OF PROPANE WILL PRODUCE APPROX. 36,000 BTU @ 0 DEGRESS, 51,000 @ 20 DEGREES.
20 percent of 100 pounds is 20 pounds. Therefore, if there is 20 percent left in a 100-pound propane tank, there are 20 pounds of propane remaining in the tank.
Ratios in Balanced Chemical ReactionsWhen you write a balanced chemical equation, the number of atoms that go into the reaction (as reactant) must equal the number of atoms that come out as products (for each type of atom). To balance a chemical equation, you must use coefficients in front of molecules to make these numbers come out right so that the reaction is balanced. Stoichiometry allows you to use these coefficients to predict how much of a certain molecule you will create for a reaction if you put in a certain amount of reactants. Let me illustrate with an example (which is the burning of propane gas in oxygen to form carbon dioxide and water):C3H8 + O2 --> CO2 + H2OThis reaction is not balanced though (Look at how many C atoms go in and how many come out. Do the same with O and H. More go in than come out, right?). Instead it should be:C3H8 + 5O2 --> 3CO2 + 4H2OThis balanced reaction tells us then that for each propane molecule, C3H8, that is burned, it will produce 3 molecules of carbon dioxide, CO2, and also 4 molecules of water, H2O. The ratio is 1 to 3 for carbon dioxide, and 1 to 4 for water. I can also say that if I know that I burned propane, and I produced 8 molecules of water, I know that I must have burned 2 molecules of C3H8.The ratio is always 1 to 4, just like in balanced reaction above. It is all based on the ratio of the coefficients. I haven't mention oxygen yet, but it's the same thing. If I burn 1 molecule of propane, I'll need 5 of O2 in order for the reaction to work. The ratio here is 1 to 5. I can even say that if I burned propane and I get 5 molecules of water out, than I must have used 5 molecules of oxygen (and 1 molecule of propane, and also I got out 3 molecules of carbon dioxide along with the water!). The ratio is then 1:5:3:4, which is just like in the balanced reaction above. Note that we usually don't talk about single molecules burning, but rather moles of molecules (which is just a whole lot of molecules). The same rules work in exactly the same way with moles. If I burn 5 moles of propane, I know I will produce 15 moles of carbon dioxide and 20 moles of water. Or if I use up 5 moles of oxygen burning propane, I'll have burned 1 mole of propane, and made 3 moles of CO2 and 4 moles of H2O.it is the study of relative proportions in which substances react or in which elements form compounds.
0.2 moles C6H12O6 x 6.02x10^23 molecules/mole = 1.2x10^23 molecules of C6H12)61.2x10^23 molecules C6H12O6 x 6 molecules "O"/molecule C6H12O6 = 7.2x19^23 molecules "O"
Propane is measured and sold in pounds