400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
400 g of calcium cabonate is equal to 3,996 moles.
One carbon dioxide molecule is produced in one particle.
The volume is 0,82 L.
To find the mass of O2 that will react with 400 g of C4H10, first calculate the moles of C4H10 using its molar mass. Then, using the balanced chemical equation for the reaction between C4H10 and O2, determine the mole ratio between C4H10 and O2. Finally, convert the moles of C4H10 to moles of O2 and then to grams of O2 using the molar mass of O2.
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
The answer is 2,4 moles.
400 g of calcium cabonate is equal to 3,996 moles.
.400 moles
The answer is 0,16 moles.
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
One carbon dioxide molecule is produced in one particle.
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
To calculate the number of moles of NaI in 50.0mL of a 0.400M solution, you first need to convert the volume to liters by dividing by 1000 (since 1L = 1000mL). Then, use the formula moles = Molarity x Volume (in liters) to find the number of moles of NaI. In this case, it would be 0.400 mol/L x 0.050 L = 0.020 moles of NaI.
So you want 0.04M but you have 400ml, not a litre. 0.04/1000*400 is 0.016 moles wanted. 0.016*40 (molecular weight) is 0.64g
The volume is 0,82 L.