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How do you calculate the number of moles of NaI in 50.0mL of a 0.400M solution?
Wiki User
∙ 12y ago
First convert mL to liters. So .05L. We know that we have .400 moles/liter, so multiply .05L*.400 mol/L and the L cancels out, leaving us with .02 moles.
Wiki User
∙ 12y ago
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How do you determine the number of grams of an active ingredient in a solution based on the percent strength?
1 1/2 cup kidney beans
What is the molarity of the following solution 1.0 moles of KCl in 500mL of solution?
You need to bring this to a litre. If there is 1 mole in 500ml (using ratio), there will be 2 moles in a litre. So your molarity is 2.
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You weight 14,5 gramm KOH in a bottle and than fill that bottle with deionized water till it holds 500ml.
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The concentration of this solution (in NaOH) is 40 g/L.
How do you determine the number of grams of an active ingredient in a solution based on the percent strength?
1 1/2 cup kidney beans
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What is the molarity of the following solution 1.0 moles of KCl in 500mL of solution?
You need to bring this to a litre. If there is 1 mole in 500ml (using ratio), there will be 2 moles in a litre. So your molarity is 2.
What is the molarity of a solution that contains 93.5g of potassium chloride dissolved in 500ml of solution?
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How will you prepare 500ml of 1N KOH solution?
You weight 14,5 gramm KOH in a bottle and than fill that bottle with deionized water till it holds 500ml.
How much ethanoic acid is needed to make 500ml of 0.1M solution?
The answer is 3grams dude!
How do you change 500ml into liters?
You divide that number by 1000.
How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?
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How is 500 ml of 0.25-M solution prepared?
The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).
How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
If you dilute 100 ml of a 7 percent solution to 500 ml what is the new percentage strength of the solution?
Simple equality. (100ml)(7%) = (500ml)(X%) = 1.4%
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