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A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.

Q: How many moles of CaCl2 does 2.41 x 10 to the 24th formula units represent?

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1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2

mom

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2

How many formula units of sodium acetate are in 0.87 moles of sodium acetat

5.68 mol MgO x 6.02E23 formula units / 1 mol = 3.42E24 Formula Units

Related questions

1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2

mom

The answer is 3,33 moles.

The answer is 2,09 moles.

It represents the amount of the substance. It can mean the number of atoms, molecules, formula units, or moles.

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2

0.688 moles*6.02x1023=4.14x1023 Formula units

10.2g

10 formula units

The answer is 5,978 moles.

How many formula units of sodium acetate are in 0.87 moles of sodium acetat

5.68 mol MgO x 6.02E23 formula units / 1 mol = 3.42E24 Formula Units