1 mole CaCl2 = 6.022 x 1023 formula units CaCl2
1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
1,290.24
mom
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
0.89 moles of CaCl2 is equal to 98.8g.
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
377.332g (anhydrous) 438.5966g (monohydrate) 499.8476g (dihydrate) 622.353g (tetrahydrate) 744.872g (hexahydrate)
mom
The answer is 3,33 moles.
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
The answer is 2,09 moles.
There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
0.89 moles of CaCl2 is equal to 98.8g.
The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================
This depends of the concentration of CaCl2 in this solution.
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2