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1 mole CaCl2 = 6.022 x 1023 formula units CaCl2

1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2

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Q: How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?
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Related questions

How many moles of CaCl2 contain 1.261024 formula units of CaCl2?

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How many moles of CaCl2 are in 2.00 1024 formula units?

The answer is 3,33 moles.


How many moles of CaCl2 does 2.41 x 10 to the 24th formula units represent?

A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.


How many moles of CaCl2 contains 1.26 times 10 24 formula units CaCI2?

The answer is 2,09 moles.


How many moles of CaCl2 are in 14.5 g of CaCl2?

There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.


What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?

Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.


What is the mass of 2.430 mole of CaCl2?

2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)


What is the mass of 0.89 mol of CaCl2?

0.89 moles of CaCl2 is equal to 98.8g.


How many chloride ions are in calcium chloride?

The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.


What is the number of molecules equal to 1.46 moles of CaCl2?

1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================


How many moles of solutes in 2.10 ml CaCl2?

This depends of the concentration of CaCl2 in this solution.


7.5 grams of CaCl2 is how many moles?

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2