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How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
How many grams of cacl2 are in 35.00 ml of a 0.237 m solution of cacl2 a 0.307 g b 0.460 g c 0.920 g d 1.84 g e 3.75 g?
Assuming that "m" was supposed to mean "molar" ("M" is usually used), the answer to this question can be found from the following calculation: The moles of calcium chloride present are 0.237(35/1000) = 0.00829. CaCl2 has a "molecular" mass of about 110; the product of this number and the number of grams is 0.920.
What is the molarity of a solution made by dissolving 25 grams of Mg in excess NaOH solution?
The molarity of the solution is 0.5 M.
What is the molarity of a kf(aq) solution containing 116grams of kf in 1.00 liter solution?
The molar mass of KF is 58.1 g/mol. Given that there are 116 grams of KF in the solution, this corresponds to 2 moles of KF. Therefore, the molarity of the solution is 2 M.
What is the molarity of 2.0 L sodium hydroxide solution containing 10.0 grams solute?
The molarity is 0,125 M.
How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
What is the molarity of a 2.0 L sodium hydroxide solution containing 10.0 grams of a solute?
.13 (Plato)
What is the molarity of a solution containing 2000 grams of H2SO4 in 2500 mL of water?
The molarity of a solution containing 2 000 grams of H2SO4 in 2500 mL of water is 8,156.
What is the molarity of an aqueous solution containing 22.5 grams of sucrose in 35.5 milliliters of solution?
To find the molarity, first convert the grams of sucrose to moles using its molar mass. Sucrose has a molar mass of 342.3 g/mol. Then, convert the milliliters of solution to liters. Finally, divide the moles of solute by the liters of solution to get the molarity.
How many grams of cacl2 are in 35.00 ml of a 0.237 m solution of cacl2 a 0.307 g b 0.460 g c 0.920 g d 1.84 g e 3.75 g?
Assuming that "m" was supposed to mean "molar" ("M" is usually used), the answer to this question can be found from the following calculation: The moles of calcium chloride present are 0.237(35/1000) = 0.00829. CaCl2 has a "molecular" mass of about 110; the product of this number and the number of grams is 0.920.
What is the molarity of a solution that contains 1.1 of lithium in 0.5 liters of solution?
If 1,1 is grams the molarity is 0,317.
What is the molarity of a solution made by dissolving 25 grams of Mg in excess NaOH solution?
The molarity of the solution is 0.5 M.
What is the molarity of a kf(aq) solution containing 116grams of kf in 1.00 liter solution?
The molar mass of KF is 58.1 g/mol. Given that there are 116 grams of KF in the solution, this corresponds to 2 moles of KF. Therefore, the molarity of the solution is 2 M.
How many grams of calcium chloride are needed to make a 0.01 M solution?
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
What is the molarity of a 2.0-liter solution containing 58 grams of NaCl?
To calculate the molarity, you first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is approximately 58.5 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters to get the molarity. In this case, molarity = (58 grams / 58.5 g/mol) / 2.0 L.
