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What is the mass of 2.430 mole of CaCl2?
2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
How many moles are in 1 g of Cl2?
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
What is the number of molecules equal to 1.46 moles of CaCl2?
To find the number of molecules in 1.46 moles of CaCl2, you would first calculate the molar mass of CaCl2 (110.98 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. This would give you approximately 8.80 x 10^23 molecules of CaCl2.
What is the emperical formula of a sample that has 80g Ca and 140g Cl?
The molar mass of Ca is 40 g/mol, and the molar mass of Cl is 35.5 g/mol. To find the empirical formula, we must first convert the masses to moles. 80 g Ca is 2 moles and 140 g Cl is 4 moles. To get the simplest whole number ratio, we divide by the smallest number of moles, giving us a ratio of 1 Ca to 2 Cl atoms, and the empirical formula is CaCl2.
What is the molarity of a solution that contains 612 grams of CaCl2 in 3.04 liters of solution?
To find the molarity, first calculate the number of moles of CaCl2. The molar mass of CaCl2 is approximately 110.98 g/mol. Thus, 612 grams of CaCl2 is about ( \frac{612 , \text{g}}{110.98 , \text{g/mol}} \approx 5.52 , \text{mol} ). The molarity (M) is then calculated as moles of solute divided by liters of solution: ( M = \frac{5.52 , \text{mol}}{3.04 , \text{L}} \approx 1.81 , \text{M} ).
How many moles are present in 140.g of Cacl2?
To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.
How many grams of CaCl2 equal 3.40 moles of CaCl2?
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
How many grams of Cl are in 435 g of CaCl2?
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
What is the mass of 2.430 mole of CaCl2?
2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
How many moles of CaCl2 contain 1.261024 formula units of CaCl2?
To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.
How many grams are in 0.74 moles of CaCl2?
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
7.5 grams of CaCl2 is how many moles?
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
How many moles of CaCl2 are in 2.00 1024 formula units?
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
How many grams of CaCl2 can be obtained if 14.6 g HCl is allowed to react with excess CaCO3?
The balanced chemical equation for the reaction between HCl and CaCO3 is: 2HCl + CaCO3 → CaCl2 + H2O + CO2. The molar ratio between HCl and CaCl2 is 2:1. Calculate the number of moles of HCl from 14.6 g, then use the mole ratio to find the moles of CaCl2. Finally, convert moles of CaCl2 to grams.
How many moles of CaCl2 does 2.41 x 10 to the 24th formula units represent?
To find the number of moles of CaCl2, first calculate the molar mass of CaCl2: Ca: 40.08 g/mol Cl: 35.45 g/mol (x2 since there are two Cl atoms) Total molar mass: 40.08 + 35.45(2) = 110.98 g/mol Next, calculate the number of moles: 2.41 x 10^24 formula units / Avogadro's number (6.022 x 10^23) = 4 moles of CaCl2.
What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
How many grams of cacl2 are in 35.00 ml of a 0.237 m solution of cacl2 a 0.307 g b 0.460 g c 0.920 g d 1.84 g e 3.75 g?
Assuming that "m" was supposed to mean "molar" ("M" is usually used), the answer to this question can be found from the following calculation: The moles of calcium chloride present are 0.237(35/1000) = 0.00829. CaCl2 has a "molecular" mass of about 110; the product of this number and the number of grams is 0.920.
