2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
What is cacl2ything? Molar mass of CaCl2 is 111 g/mol Best guess for an answer to your confusing question is 4.79 x 10-2 mole x 111 g/mole = 5.3169 grams
Calcium chloride with formula CaCl2 has molecular mass of 141. Commercial calcium chloride has formula CaCl2,2H2O.It's molecular mass is 177.
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
To find the number of molecules in 1.46 moles of CaCl2, you would first calculate the molar mass of CaCl2 (110.98 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. This would give you approximately 8.80 x 10^23 molecules of CaCl2.
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
To find the mass of CaCl2 needed, you need to use the formula: Mass = molarity × volume × molar mass. First, calculate the number of moles of CaCl2 using the molarity and volume. Then, multiply the moles by the molar mass of CaCl2 (110.98 g/mol) to find the mass needed. A 1.56 M solution means it contains 1.56 moles of CaCl2 in 1 liter of solution.
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
What is cacl2ything? Molar mass of CaCl2 is 111 g/mol Best guess for an answer to your confusing question is 4.79 x 10-2 mole x 111 g/mole = 5.3169 grams
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
Calcium chloride with formula CaCl2 has molecular mass of 141. Commercial calcium chloride has formula CaCl2,2H2O.It's molecular mass is 177.
2 HCl + CaCO3 -> CaCl2 + H2O + CO2 In words, two moles of hydrochloric acid reacts with one mole of calcium carbonate to yield one mole of calcium chloride, one mole of water, and one mole of carbon dioxide.
In one mole of CaCl2, there are 2 moles of chloride ions since there are 2 chloride ions for every 1 CaCl2 molecule. Therefore, there are 2 * 6.022 x 10^23 = 1.2044 x 10^24 chloride ions in one mole of CaCl2.
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.