By definition, one mole would be the same as the molecular mass. You take the number of moles and multiply it by the molecular mass. So if you have just 1 mole, the number of grams will be the added atomic masses of the elements in the compound.
Ca- 40.08
Cl- 35.5
CaCl- 75.6 grams
calcium chloride always contains ______ grams of chlorine for each 1 gram of calcium.
calicum cloride.
n= 6,0/112
n= 0.05 mol
17
mom
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
377.332g (anhydrous) 438.5966g (monohydrate) 499.8476g (dihydrate) 622.353g (tetrahydrate) 744.872g (hexahydrate)
1.26 moles
There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.
mom
This depends of the concentration of CaCl2 in this solution.
The answer is 3,33 moles.
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
The answer is 2,09 moles.
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
377.332g (anhydrous) 438.5966g (monohydrate) 499.8476g (dihydrate) 622.353g (tetrahydrate) 744.872g (hexahydrate)
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g