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377.332g (anhydrous)

438.5966g (monohydrate)

499.8476g (dihydrate)

622.353g (tetrahydrate)

744.872g (hexahydrate)

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7.5 grams of CaCl2 is how many moles?

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2


How many moles of CaCl2 contain 1.261024 formula units of CaCl2?

To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.


How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?

The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.


How many moles are present in 18.4g of CaCl2?

By definition, one mole would be the same as the molecular mass. You take the number of moles and multiply it by the molecular mass. So if you have just 1 mole, the number of grams will be the added atomic masses of the elements in the compound.Ca- 40.08Cl- 35.5CaCl- 75.6 grams


How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?

Oh, dude, let me break it down for you. So, 1 mole of CaCl2 contains 6.022 x 10^23 formula units, right? And you've got 1.26 x 10^24 formula units of CaCl2. So, you just divide 1.26 x 10^24 by 6.022 x 10^23 to get the number of moles. Easy peasy, lemon squeezy!

Related Questions

7.5 grams of CaCl2 is how many moles?

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2


How many grams of Cl are in 435 g of CaCl2?

There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.


How many grams are in 0.74 moles of CaCl2?

Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g


How many grams of CaCl2 can be obtained if 14.6 g HCl is allowed to react with excess CaCO3?

The balanced chemical equation for the reaction between HCl and CaCO3 is: 2HCl + CaCO3 → CaCl2 + H2O + CO2. The molar ratio between HCl and CaCl2 is 2:1. Calculate the number of moles of HCl from 14.6 g, then use the mole ratio to find the moles of CaCl2. Finally, convert moles of CaCl2 to grams.


How many moles are in 0.377 grams of Kr?

0.377 grams of Kr is equal to 0,0045 moles.


How many moles of C2H6 are in 124 grams?

124 grams of ethane is equal to 4,124 moles.


How many moles are there in 370 grams of mercury?

370 grams of mercury is equal to 1,844 moles.


How many moles of CaCl2 are in 14.5 g of CaCl2?

There are 0.07871604895385 moles of CaC12 in 14.5g of CaC12.


How many moles of aluminum are in 1.99 grams of aluminum?

1,99 grams of aluminum is equal to 0,0737 moles.


How many moles of nitrogen are in 15 grams of nitrogen?

15 grams of nitrogen are equal to 1,071 moles.


How many moles are in 6.5 grams of sulfur S?

6,5 grams of sulfur S are equal to 0,203 moles.


How many moles are In 89 grams of PbCH3COO4?

89 grams of Pb(CH3COO)4 is equal to 0,2 moles.