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The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;

as dihydrate CaCl2.2H2O it is: 147,01 g/mol

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What is the gram formula mass of CaCl2?

The gram formula mass of CaCl2 is approximately 110.98 g/mol. This is calculated by adding the atomic masses of the elements in the compound, which are 40.08 g/mol for calcium (Ca) and 35.45 g/mol for each chlorine (Cl) atom.


What is the mass of 0.89 mol of CaCl2?

To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.


How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?

The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.


What is the mass of 2.430 mole of CaCl2?

2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)


7.5 grams of CaCl2 is how many moles?

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2


What mass of CaCL2 is needed to prepare 2.850 L of a 1.56 M solution?

To find the mass of CaCl2 needed, you need to use the formula: Mass = molarity × volume × molar mass. First, calculate the number of moles of CaCl2 using the molarity and volume. Then, multiply the moles by the molar mass of CaCl2 (110.98 g/mol) to find the mass needed. A 1.56 M solution means it contains 1.56 moles of CaCl2 in 1 liter of solution.


How many moles are present in 140.g of Cacl2?

To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.


What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?

First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.


How many grams of CaCl2 equal 3.40 moles of CaCl2?

The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.


What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?

Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.


How many grams are in 0.74 moles of CaCl2?

Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g


How many grams calcium are in 100 grams calcium chloride?

The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.