0.89 moles of CaCl2 is equal to 98.8g.
Ca + Cl + Cl = 40.078 +35.453 + 35.453 = 110.984 .89 / 110.984 = 0.008019
The molar mass of CaCN2 = 80.1021 g/mol
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
2 m
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
Ca + Cl + Cl = 40.078 +35.453 + 35.453 = 110.984 .89 / 110.984 = 0.008019
To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.
The molar mass of CaCN2 = 80.1021 g/mol
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
The gram formula mass of CaCl2 is approximately 110.98 g/mol. This is calculated by adding the atomic masses of the elements in the compound, which are 40.08 g/mol for calcium (Ca) and 35.45 g/mol for each chlorine (Cl) atom.
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
Molarity = moles of solute/Liters of solution 0.320 M CaCl2 = moles CaCl2/4.5 Liters = 1.44 moles of CaCl2 1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2) = 159.81 grams needed so, considering the sigi figis, 160 grams needed.
2 m
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
The molar mass of calcium is 40.08 g/mol and chlorine is 35.45 g/mol. The number of moles of calcium is 3.609g / 40.08 g/mol = 0.09 mol, and for chlorine it is 6.384g / 35.45 g/mol = 0.18 mol. The ratio of moles is 0.09 mol Ca to 0.18 mol Cl, thus the empirical formula is CaCl2.