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What is the mass of 0.89 mol of CaCl2?
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
7.5 grams of CaCl2 is how many moles?
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
How many grams of CaCl2 equal 3.40 moles of CaCl2?
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
How many moles of CaCl2 contain 1.261024 formula units of CaCl2?
To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.
Find the mass of 0.89 mol of CaCl2?
Ca + Cl + Cl = 40.078 +35.453 + 35.453 = 110.984 .89 / 110.984 = 0.008019
How many grams are in 0.74 moles of CaCl2?
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
What is the mass of 0.89 mol of CaCl2?
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
7.5 grams of CaCl2 is how many moles?
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
How many moles are present in 140.g of Cacl2?
To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.
What is the molecular weight of CaCl2 using these values C 12 H 1 Ca 40 Cl 35?
The exact molar weight of calcium chloride is 110,978 g/mol.
How would you make 1 liter of a 1 molar solution of CaCl2?
To make 1 liter of a 1 molar solution of CaCl2, you would need to dissolve 147.02 grams of CaCl2 in enough water to make a final volume of 1 liter. This formula weight comes from the atomic weights of calcium (40.08 g/mol) and chlorine (35.45 g/mol).
What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.
How many grams of CaCl2 equal 3.40 moles of CaCl2?
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
What mass of CaCL2 is needed to prepare 2.850 L of a 1.56 M solution?
To find the mass of CaCl2 needed, you need to use the formula: Mass = molarity × volume × molar mass. First, calculate the number of moles of CaCl2 using the molarity and volume. Then, multiply the moles by the molar mass of CaCl2 (110.98 g/mol) to find the mass needed. A 1.56 M solution means it contains 1.56 moles of CaCl2 in 1 liter of solution.
What is the gram fromula mass of CaCl2?
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
How many moles of CaCl2 contain 1.261024 formula units of CaCl2?
To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.
What coefficient is needed to balance CaCl2 H2CO3 CaCO3 HCl?
CaCl2 + H2CO3 = CaCO3 + 2HCl The molar ratios (coefficients) are 1:1::1:2
