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How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
What 1 molar aqueous solution has the highest number density of ions 1 Glucose 2 CaCl2 3 NaNO3 4 KCl?
CaCl2 would have the highest number density of ions since it dissociates into 3 ions: one Ca2+ ion and two Cl- ions. This results in a total of 3 ions in solution per formula unit of CaCl2.
How do you prepare 0.1n hypona2s2o4?
Let me translate the question: I think you are asking how to make a 0.1 molar solution of Na2S2O4. Molarity is moles of solute divided by liters of solution. To make this easy, let's assume you want to make one liter of the solution. That means you need to dissolve in 0.1 moles of Na2S2O4 into one liter of water to make a 0.1 molar solution. The formula weight of Na2S2O4 is 174.1 grams per mole so 0.1 moles of it is 17.41 grams. Therefore you would need to dissolve 17.41 grams of Na2S2O4 into one liter of water to make a 0.1 molar solution.
How many grams are in 0.74 moles of CaCl2?
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
How many grams of KCl is needed to make 2 molar solution in 1 liter of water?
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
1 Molar solution of Lactose?
342 grams of Lactose in 1 litre water or 34.2 grams in 100 mls.
What is the mass of 0.89 mol of CaCl2?
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
What 1 molar aqueous solution has the highest number density of ions 1 Glucose 2 CaCl2 3 NaNO3 4 KCl?
CaCl2 would have the highest number density of ions since it dissociates into 3 ions: one Ca2+ ion and two Cl- ions. This results in a total of 3 ions in solution per formula unit of CaCl2.
How do you prepare 0.1n hypona2s2o4?
Let me translate the question: I think you are asking how to make a 0.1 molar solution of Na2S2O4. Molarity is moles of solute divided by liters of solution. To make this easy, let's assume you want to make one liter of the solution. That means you need to dissolve in 0.1 moles of Na2S2O4 into one liter of water to make a 0.1 molar solution. The formula weight of Na2S2O4 is 174.1 grams per mole so 0.1 moles of it is 17.41 grams. Therefore you would need to dissolve 17.41 grams of Na2S2O4 into one liter of water to make a 0.1 molar solution.
How much water should be added to 98 mg of sodium azide to give a 1 molar solution?
To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.
How many grams are in 0.74 moles of CaCl2?
Atomic Weight of Calcium = 40 Atomic Weight of Chlorine = 35.5 Therefore, 1 mole of CaCl2 => 40 + 2 (35.5) = 111 g 0.74 moles of CaCl2 => 0.74 (111) = 82.14 g
How many grams of KCl is needed to make 2 molar solution in 1 liter of water?
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
How many grams of calcium chloride are needed to make a 0.01 M solution?
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
How many grams of CaCl2 equal 3.40 moles of CaCl2?
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.
Can you prepare 1 liter of a .5-molar glucose solution?
To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.
