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What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How can prepare .01N KBr solution?
To prepare a 0.01N KBr solution, dissolve 0.74g of KBr in 1 liter of water. This will give you a solution with a molarity of 0.01N for KBr.
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
How do you prepare 0.1N potassium permanganate?
To prepare 0.1N potassium permanganate solution, dissolve 3.16 grams of potassium permanganate in 1 liter of water. This will give you a solution with a normality of 0.1N.
What does 1M glucose solution mean?
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How can prepare .01N KBr solution?
To prepare a 0.01N KBr solution, dissolve 0.74g of KBr in 1 liter of water. This will give you a solution with a molarity of 0.01N for KBr.
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
How much glucose is in one liter of 5 percent dextrose in water?
A 5 percent dextrose solution contains 5 grams of dextrose (glucose) per 100 milliliters of solution. Therefore, in one liter (1000 milliliters) of a 5 percent dextrose solution, there would be 50 grams of glucose.
How many molecules of glucose would be in 1 liter of the 1 m?
1 mole of glucose contains 6.022 x 10^23 molecules. In a 1 M solution, there would be 1 mole of glucose dissolved in 1 liter of solution, so there would be 6.022 x 10^23 molecules of glucose in 1 liter of the solution.
What is the osmolarity of 5.5 percent glucose solution?
To calculate the osmolarity of a 5.5% glucose solution, first convert the percentage to grams per liter: 5.5% means 5.5 grams of glucose per 100 mL, which is 55 grams per liter. Glucose (C6H12O6) has a molar mass of approximately 180 g/mol, so 55 grams corresponds to about 0.306 moles per liter (55 g / 180 g/mol). Since glucose does not dissociate in solution, the osmolarity is equal to its molarity, which is approximately 0.306 osmoles per liter.
How do you prepare 1 liter of 100ppm NaCl solution?
To prepare a 1 liter of 100ppm NaCl solution, you would dissolve 0.1 grams of NaCl in 1 liter of water. This concentration is achieved by mixing 0.1 grams of NaCl in 1 liter of water.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
If you have a liter of water with 200g of glucose in it what is the mass vol percent of glucose in that solution?
200 grams/1,000 mL x 100= 20%
How do you prepare 0.1N potassium permanganate?
To prepare 0.1N potassium permanganate solution, dissolve 3.16 grams of potassium permanganate in 1 liter of water. This will give you a solution with a normality of 0.1N.
How many ml are needed to prepare 1 liter of 2.5 percent dextrose solution?
25
How many grams of Glucose molecular formula C6O6H12 should you dissolve in 1 liter of water to get 1 molar solution?
To make a 1 molar solution of glucose (C6H12O6) in 1 liter of water, you would need to dissolve 180 grams of glucose. This is because the molar mass of glucose is 180 g/mol, so 1 mole of glucose weighs 180 grams.
