10 formula units
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∙ 2016-07-15 17:01:09The answer is 5,978 moles.
The answer is 32,4.10e23.
13,1581 moles contain 81,7867.10e23 molecules (or ions, atoms).
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
The answer is 2,09 moles.
One mole of formula units = 6.022 x 1023 formula units.
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
The answer is 3,33 moles.
The answer is 5,978 moles.
3 moles of FeCl2 is equivalent to 380,253 g. And 3 moles contain 18,066 422 571.10e23 formula units.
The answer is 8 moles.
The answer is 32,4.10e23.
13,1581 moles contain 81,7867.10e23 molecules (or ions, atoms).
There is 1.42 x 10^-2 moles of formula units that are in 5.67 g of iron III sulfate.
The result is 0,921.10e14 moles.
Approx. 1,5.1023 molecules.
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