42.394 grams.
42.394
1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
Molarity = moles of solute/Liters of solution ( 250.0 ml = 0.250 liters ) Find moles. 61.7 grams LiCl (1 mole/42.391 grams) = 1.455 moles lithium chloride Molarity = 1.455 moles LiCl/0.250 liters = 5.82 M LiCl -------------------
Molarity = moles of solute/Liters of solution ( 230 ml = 0.0230 Liters) Molarity = 2.60 moles LiCl/0.230 Liters = 11. 3 M LiCl -----------------
LiCl has ionic bonding. (There is no compound with a formula LiCL.)
This is the chemical formula of sodium chloride.
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
The formula mass of the ionic compound lithium chloride, LiCl is 6.9 + 35.5 = 42.4.Amount of LiCl = 98.2/42.4 = 2.32molThere are 2.32 moles of formula unit in a 98.2g pure sample of LiCl.To get the numerical number, multiply the quantity in moles by the Avogadro's constant.
1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
You know because of solubility rules that LiCl disassociates 100% in water. So, knowing that molarity is equal to moles/liters Molarity LiCl = 1.97mol / 33.2 L Molarity = 0.059 M LiCl
Molarity = moles of solute/Liters of solution ( 250.0 ml = 0.250 liters ) Find moles. 61.7 grams LiCl (1 mole/42.391 grams) = 1.455 moles lithium chloride Molarity = 1.455 moles LiCl/0.250 liters = 5.82 M LiCl -------------------
Molarity = moles of solute/Liters of solution ( 230 ml = 0.0230 Liters) Molarity = 2.60 moles LiCl/0.230 Liters = 11. 3 M LiCl -----------------
There are 50 moles in 5 liters of 10 M LiCl (10 molar lithium chloride).
LiCl has ionic bonding. (There is no compound with a formula LiCL.)
Formula: LiCl
Remember the equation # moles = mass(g) / Mr ( Relative molcular mass) The Mr of LiCl is: - 1 x Li = 1 x 7 = 7 1 x Cl = 1 x 35.5 = 35.5 7 + 35.5 = 42.5 Substituting moles(LiCl) = 0.55 g/ 42.5 = 0.0129... ~ 0.013
LiCl+H2SO4=LiHSO4+HCl