The formula mass of the ionic compound lithium chloride, LiCl is 6.9 + 35.5 = 42.4.Amount of LiCl = 98.2/42.4 = 2.32mol
There are 2.32 moles of formula unit in a 98.2g pure sample of LiCl.
To get the numerical number, multiply the quantity in moles by the Avogadro's constant.
How many formula units of Fe2O3 are used in the process to produce 740 g of Fe?
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
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This question needs clarification, because "formula units" can mean either the number of atoms to constitute one formula or Avogadro's Number of such formula units, although the latter should more precisely described as "gram formula units".
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
42.394 grams.
1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
10 formula units
The answer is 5,21131981201352.10e23 formula units of silver nitrate.
How many grams of NaCl are present in 8.39x10^22 formula units of NaCl?
The number of formula units is 0,602 214 085 7.10e23.
How many formula units of Fe2O3 are used in the process to produce 740 g of Fe?
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
The number of formula units of NaCl is 11335.10e17.
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