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A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?
To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.
How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?
To calculate the number of grams of LiCl required, you need to use the formula: ( \text{grams} = \text{Molarity} \times \text{Volume} \times \text{Molar Mass} ) Given that the molar mass of LiCl is approximately 42.39 g/mol, plug in the values and calculate the grams of LiCl needed.
How many formula units of sodium acetate are in 0.87 moles of sodium acetate?
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
How many loaned pairs of electrons does LiCl have?
LiCl does not have any loaned pairs of electrons. In LiCl, lithium donates one electron to chlorine to form an ionic bond, leading to a full outer shell for both elements.
How many formula units are in 5.6 g of H2S?
To calculate the number of formula units in 5.6 g of H2S, you first need to determine the molar mass of H2S, which is 34.08 g/mol. Then, you can use the formula: Number of formula units = (mass given / molar mass) * Avogadro's number. Plugging in the values, you get: (5.6 g / 34.08 g/mol) * 6.022 x 10^23 = 9.89 x 10^22 formula units in 5.6 g of H2S.
How many formula units of LiCl are equal to .648 moles?
42.394 grams.
How many formula units of LiCl are in a 127.17 g sample?
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
How many formula units of LiCl are in 127.17 g sample?
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
How many molecules are in LiCi are in a 127.17 g sample?
To determine the number of molecules in a sample of LiCl, we need to first calculate the number of moles using the molar mass of LiCl (42.39 g/mol). Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, there are approximately (127.17 \text{ g} / 42.39 \text{ g/mol} \approx 3 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} ≈ 1.8 \times 10^{24}) molecules of LiCl in 127.17 g.
How many formula units of salt make up 10 moles?
10 formula units
How many grams of LiCl would you use to make 20 ml of a 4M solution?
To make a 4M solution in 20 ml, you would need 0.32 grams of LiCl. This can be calculated using the formula: moles = molarity x volume (in L), then converting moles to grams using the molar mass of LiCl.
A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?
To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.
How many grams of NaCl are present in 8.39x1022 formula units of NaCl?
How many grams of NaCl are present in 8.39x10^22 formula units of NaCl?
How many formula units are 0.1 mole of CaS?
The number of formula units is 0,602 214 085 7.10e23.
How many atoms are in LiCI?
Li is lithium. Never heard of Ci.Do you mean Cl? That would be Lithium Chloride LiCl...
How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?
To calculate the number of grams of LiCl required, you need to use the formula: ( \text{grams} = \text{Molarity} \times \text{Volume} \times \text{Molar Mass} ) Given that the molar mass of LiCl is approximately 42.39 g/mol, plug in the values and calculate the grams of LiCl needed.
How many NaCl formula units make up 0.11 grams of salt crystals?
The number of formula units of NaCl is 11335.10e17.
