The answer is 32,4.10e23.
To find the number of moles of potassium nitrate (KNO3) from the given formula units, we use Avogadro's number, which is approximately (6.022 \times 10^{23}) formula units per mole. We can calculate the moles by dividing the number of formula units by Avogadro's number: [ \text{Moles of KNO3} = \frac{8.68 \times 10^{20}}{6.022 \times 10^{23}} \approx 0.00144 \text{ moles} ] Thus, there are approximately 0.00144 moles of potassium nitrate in 8.68 x (10^{20}) formula units.
0.688 moles*6.02x1023=4.14x1023 Formula units
10 formula units
The answer is 5,978 moles.
The chemical formula 8K2SO4 represents 8 units of potassium sulfate. Each unit contains 2 potassium (K) atoms, 1 sulfur (S) atom, and 4 oxygen (O) atoms, totaling 2 + 1 + 4 = 7 atoms per unit. Therefore, for 8 units, the total number of atoms is 8 x 7 = 56. The formula represents 8 molecules of potassium sulfate.
To find the moles of formula units in 5.67 g of iron III sulfate, you first need to calculate the molar mass of Fe2(SO4)3. The molar mass is 399.9 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 5.67 g / 399.9 g/mol = 0.0142 moles of formula units.
To find the number of moles of potassium nitrate (KNO3) from the given formula units, we use Avogadro's number, which is approximately (6.022 \times 10^{23}) formula units per mole. We can calculate the moles by dividing the number of formula units by Avogadro's number: [ \text{Moles of KNO3} = \frac{8.68 \times 10^{20}}{6.022 \times 10^{23}} \approx 0.00144 \text{ moles} ] Thus, there are approximately 0.00144 moles of potassium nitrate in 8.68 x (10^{20}) formula units.
To determine the number of formula units in 2.45 moles of potassium chloride, you first need to find the molar mass of KCl, which is approximately 74.55 g/mol. Then, divide the number of moles by the molar mass to get the number of formula units. Therefore, 2.45 moles of KCl is equivalent to about 163 formula units.
To determine the number of formula units in 0.0482 mol of sodium sulfate, you first need to find the molar mass of sodium sulfate (Na2SO4). The molar mass of Na2SO4 is approximately 142.04 g/mol. Then, divide the given amount of moles by the molar mass to find the number of formula units. In this case, there are approximately 3.39 x 10^22 formula units in 0.0482 mol of sodium sulfate.
One formula unit of iron III sulfate consists of one iron atom, three sulfur atoms, and 12 oxygen atoms. To calculate the number of formula units in 0.671 moles of iron III sulfate, you first need to determine the molar mass of the compound, then use the Avogadro's number (6.022 x 10^23) to convert moles to formula units.
0.688 moles*6.02x1023=4.14x1023 Formula units
To determine the number of moles of iron sulfate in 5.67g, you need to first calculate the molar mass of iron sulfate (FeSO4). The molar mass of FeSO4 is approximately 151.91 g/mol. Next, divide the given mass by the molar mass to find the number of moles. 5.67g / 151.91 g/mol ≈ 0.0373 moles of FeSO4.
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
To find the number of formula units of magnesium oxide in 5.68 moles, you first need to determine the formula of magnesium oxide (MgO). Then use Avogadro's number (6.022 x 10^23) to convert moles to formula units. So, in 5.68 moles of MgO, there are approximately 3.43 x 10^24 formula units.
10 formula units
The answer is 5,978 moles.
The chemical formula 8K2SO4 represents 8 units of potassium sulfate. Each unit contains 2 potassium (K) atoms, 1 sulfur (S) atom, and 4 oxygen (O) atoms, totaling 2 + 1 + 4 = 7 atoms per unit. Therefore, for 8 units, the total number of atoms is 8 x 7 = 56. The formula represents 8 molecules of potassium sulfate.