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2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)

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8y ago
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8y ago

The mass of 2,430 moles of anhydrous CaCl2 is 269,68 g.

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Q: What is the mass of 2.430 mole of CaCl2?
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7.5 grams of CaCl2 is how many moles?

For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2


What mass of CaCL2 is needed to prepare 2.850 L of a 1.56 M solution?

2.850 L x (1.56 moles CaCl2 / 1 L) x (111.0 g CaCl2 / mole CaCl2) = 493g


What is the mass of 4.7910-2 mol cacl2ything?

What is cacl2ything? Molar mass of CaCl2 is 111 g/mol Best guess for an answer to your confusing question is 4.79 x 10-2 mole x 111 g/mole = 5.3169 grams


How many grams of calcium chloride will you add to 250mL of water to make a 0.236 M solution?

Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g


How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?

1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2


How many moles are in 1 g of Cl2?

# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol


How many grams of Cl are in 385 g of CaCl?

246 g


What is the number of molecules equal to 1.46 moles of CaCl2?

1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================


What is the mass of 0.89 mol of CaCl2?

0.89 moles of CaCl2 is equal to 98.8g.


What is the number of molecules equal to 1.46 moles for CaCl2?

1.46 Moles CaCl2 (6.022 X 10^23/1 mole CaCl2) = 8.79 X 10^23 molecules of calcium chloride


How many moles of CaCl2 does 2.41 x 10 to the 24th formula units represent?

A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.


What is the gram fromula mass of CaCl2?

The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol