2.430 moles CaCl2 x 110.98 g CaCl2/mole CaCl2 = 269.7 grams (4 sig figs)
The mass of 2,430 moles of anhydrous CaCl2 is 269,68 g.
What is cacl2ything? Molar mass of CaCl2 is 111 g/mol Best guess for an answer to your confusing question is 4.79 x 10-2 mole x 111 g/mole = 5.3169 grams
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
111g
For this you need the atomic (molecular) mass of CaCl2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CaCl2=111.1 grams7.5 grams CaCl2 / (111.1 grams) = .0675 moles CaCl2
2.850 L x (1.56 moles CaCl2 / 1 L) x (111.0 g CaCl2 / mole CaCl2) = 493g
What is cacl2ything? Molar mass of CaCl2 is 111 g/mol Best guess for an answer to your confusing question is 4.79 x 10-2 mole x 111 g/mole = 5.3169 grams
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
246 g
1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================
0.89 moles of CaCl2 is equal to 98.8g.
1.46 Moles CaCl2 (6.022 X 10^23/1 mole CaCl2) = 8.79 X 10^23 molecules of calcium chloride
A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol