0
What else can I help you with?
How will you convert the masses of anhydrous CuSO4 and water to moles?
To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
Please help me The balance formula MgSo4 2NaOH MgOH Na2SO4 125 g of MgSO4 115 g of NaOH what is the mass of milk of magnesia MgOH2 produced?
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
How do you convert 5.2 moles of Epsom salt to grams?
The chemical formula of hydrated Epsom salt is MgSO4.7H2O. The molar mass is 246,47 grams. 5,2 X 246,47 = 1281,644 grams
How many moles of Magnesium Hydroxide can be expected from 0.01246 moles MgSO4?
Do you mean from this reaction? MgSO4 + 2H2O -> Mg(OH)2 + H2SO4 let us assume water is in excess 0.01246 MgSO4 (1 mole Mg(OH)2/1 mole MgSO4) = 0.01246 moles Mg(OH)2 produced ----------------------------------------------- This reaction is one to one.
How many formula units are in 0.75 moles of AlCl3?
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
How will you convert the masses of anhydrous CuSO4 and water to moles?
To convert the masses of anhydrous CuSO4 and water to moles, you would use the formula: moles = mass (grams) / molar mass (g/mol). First, determine the molar mass of anhydrous CuSO4 (approximately 159.61 g/mol) and water (approximately 18.02 g/mol). Then, divide the mass of each substance by its respective molar mass to obtain the number of moles.
How many moles are present in 480g of anhydrous magnesium sulfate?
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
Please help me The balance formula MgSo4 2NaOH MgOH Na2SO4 125 g of MgSO4 115 g of NaOH what is the mass of milk of magnesia MgOH2 produced?
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
How many moles of each ion are found in a 1L of 5m of MgSo4 solution?
Molarity = moles of solute/Liters of solution5 M MgSO4 = moles MgSO4/1 L5 moles MgSO4=============since all is one to one in ion countMg 2+ = 5 moles--------------------------andSO4 2- = 5 moles----------------------
How many moles are present in 1.64g of MgSO4?
To calculate the number of moles in 1.64g of MgSO4, you first need to determine the molar mass of MgSO4 which is 120.37 g/mol. Next, divide the given mass by the molar mass to get the number of moles. In this case, 1.64g ÷ 120.37 g/mol ≈ 0.014 moles of MgSO4.
How many moles are in 7.6 grams of Epsom salts MgSO4?
Depends on if it is hydrated or not. If hydrated, magnesium sulfate heptahydrate, then (7.6g)/(246.47g/mole)=.0308mole. If anhydrous (7.6g)/(120.415g/mole)=0.063mole.
How do you convert 0.570 grams of copper sulphate to moles?
This depends on: - if it is an anhydrous or hydrated salt - if it is a salt of Cu(I) or Cu(II) For CuSO4(anh.) the answer is 0,00364 moles.
How many grams of anhydrous nickel 2 sulfate is produced from 8.753 grams of heptahydrate?
Hello, Very simply, if the molar ratio is 1:1 mole, then divide the molecular weight of the anhydrous material by the hydrated one, then multiply the result by 8.753 g. Solution: NiSO4 anhydrous molecular weight is 154.75 g/mol (anhydrous) NiSO4·7H2O molecular weight is 280.86 g/mol (heptahydrate) So: 154.75/280.86 = 0.55098 The grams quantity produced from 8.753 heptahydrate is (0.55098*8.753) = 4.823 grams anhydrous NiSO4 anhydrous Best wishes AD
How do you convert 5.2 moles of Epsom salt to grams?
The chemical formula of hydrated Epsom salt is MgSO4.7H2O. The molar mass is 246,47 grams. 5,2 X 246,47 = 1281,644 grams
How do you calculate the masses of carbon dioxide hydrogen and oxyen at STP?
If you know moles of each use their molar masses to convert to mass.
How many moles of Magnesium Hydroxide can be expected from 0.01246 moles MgSO4?
Do you mean from this reaction? MgSO4 + 2H2O -> Mg(OH)2 + H2SO4 let us assume water is in excess 0.01246 MgSO4 (1 mole Mg(OH)2/1 mole MgSO4) = 0.01246 moles Mg(OH)2 produced ----------------------------------------------- This reaction is one to one.
