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A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
Cookie333
48.8 g MgSO4 & 51.2 g H2O
Convert the mass into moles by dividing molar mass for each.
Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
Wiki User
∙ 11y ago
Wiki User
∙ 14y agoAlright... I assume ur asking this because its a hydrate so its easy peasy but because I don;t have a calculator or Periodic Table you do the math :P
FIrst find the molar mass of water and MgSO4
Then assume you have 100g of of sample... This means the mass of MgSO4 in the compound is 48.8g and the mass of H20 in the 100g sample would be 51.2g
Next, find the number of moles of MgSO4 and H2O by dividing the masses in the sample by their molar masses...
Next, divide the component with the larger number of moles by the component with the smaller number... THis gives you a ratio of how many more times of the more abundant material there is... eg) if there are more moles of H20 than MgSO4 and # mol H20/ #mol MgSO4 = 3/2, the ratio would be 2(MgSO4):3H2O
Use the ratio to fill in the formula and TADA!!
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