0.01362 moles.
Molarity = moles of solute/Liters of solution5 M MgSO4 = moles MgSO4/1 L5 moles MgSO4=============since all is one to one in ion countMg 2+ = 5 moles--------------------------andSO4 2- = 5 moles----------------------
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
5 moles
How many moles are present in 92 grams of ethyl alcohol?
9
Molarity = moles of solute/Liters of solution5 M MgSO4 = moles MgSO4/1 L5 moles MgSO4=============since all is one to one in ion countMg 2+ = 5 moles--------------------------andSO4 2- = 5 moles----------------------
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
Do you mean from this reaction? MgSO4 + 2H2O -> Mg(OH)2 + H2SO4 let us assume water is in excess 0.01246 MgSO4 (1 mole Mg(OH)2/1 mole MgSO4) = 0.01246 moles Mg(OH)2 produced ----------------------------------------------- This reaction is one to one.
1337
5 moles
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
The answer is 8,33 moles.
The answer is 0,615 moles.
How many moles are present in 92 grams of ethyl alcohol?
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
9
The answer is 14,93 moles.