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How many moles of each ion are found in a 1L of 5m of MgSo4 solution?
Molarity = moles of solute/Liters of solution5 M MgSO4 = moles MgSO4/1 L5 moles MgSO4=============since all is one to one in ion countMg 2+ = 5 moles--------------------------andSO4 2- = 5 moles----------------------
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
How many moles of H2O are present in 75.0g H2O?
There are 4.17 moles of H2O present in 75.0g of H2O.
How many molecules in 25g of MgSO4?
To find the number of molecules in 25g of MgSO4, you need to first calculate the number of moles of MgSO4 using its molar mass (120.37 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
How many moles of each ion are found in a 1L of 5m of MgSo4 solution?
Molarity = moles of solute/Liters of solution5 M MgSO4 = moles MgSO4/1 L5 moles MgSO4=============since all is one to one in ion countMg 2+ = 5 moles--------------------------andSO4 2- = 5 moles----------------------
How many moles of MgOH2 will be produced when 30g of NaOH react with MgSO4?
1337
How many moles are present in 480g of anhydrous magnesium sulfate?
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
How many moles of Magnesium Hydroxide can be expected from 0.01246 moles MgSO4?
Do you mean from this reaction? MgSO4 + 2H2O -> Mg(OH)2 + H2SO4 let us assume water is in excess 0.01246 MgSO4 (1 mole Mg(OH)2/1 mole MgSO4) = 0.01246 moles Mg(OH)2 produced ----------------------------------------------- This reaction is one to one.
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
How many moles of Mg are present in 14.95 g?
The answer is 0,615 moles.
How many moles of H2O are present in 150.0G of H2O?
The answer is 8,33 moles.
How many moles of H2O are present in 75.0g H2O?
There are 4.17 moles of H2O present in 75.0g of H2O.
How many moles of oxygen are present in a flask with 1.5 L?
The answer is 14,93 moles.
How many moles are present in 17.4 of lead?
If 17,4 is grams the number of moles is 0,084.
How many Moles of water are present in 180.00 gm of water?
9.991 Moles (water) 8.982 Moles (heavy water)
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
