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How many moles of sodium sulfate are present in 284 g?
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
How many moles of sulfate ions are there in a 0.20 Liter solution of 0.030 molar aluminum sulfide and oxygen?
To find the moles of sulfate ions in the solution, you first need to determine the moles of aluminum sulfide present. Since you are not provided with the amount of aluminum sulfide, you cannot calculate the moles of sulfate ions. Additionally, oxygen is not relevant to determining the moles of sulfate ions.
How many moles of copper sulfate are needed to make 2.50 Liters of 0.125 moles solution?
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
What happens when heating hydrate of calcium sulfate how many moles of water should be driven off per mole of hydrate?
When heating hydrate of calcium sulfate, typically two moles of water are driven off per mole of hydrate. This process is known as dehydration, where the water molecules are removed from the compound as it is heated, resulting in the formation of an anhydrous compound.
What is the mass of 0.25 moles of aluminum sulphate?
To find the mass of 0.25 moles of aluminum sulfate, you need to know the molar mass of aluminum sulfate. The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be around 85.54 grams.
How many moles of anhydrous copper sulfate is produced when 6.4 moles of hydrated copper sulfate is heated?
When hydrated copper sulfate is heated, it loses its water molecules to form anhydrous copper sulfate. Since the molar ratio between the two forms is 1:1, if 6.4 moles of hydrated copper sulfate is heated, 6.4 moles of anhydrous copper sulfate will be produced.
How many moles are 4.12 grams aluminum sulfate?
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
How many moles are in 7.6 grams of Epsom salts MgSO4?
Depends on if it is hydrated or not. If hydrated, magnesium sulfate heptahydrate, then (7.6g)/(246.47g/mole)=.0308mole. If anhydrous (7.6g)/(120.415g/mole)=0.063mole.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?
The answer is approx. 2 moles (for anhydrous sodium sulfate).
When calculating the number of moles of solid Na2SO4 the factor used is?
The molar mass of anhydrous sodium sulfate is 142,04.
How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
How many grams of anhydrous nickel 2 sulfate is produced from 8.753 grams of heptahydrate?
Hello, Very simply, if the molar ratio is 1:1 mole, then divide the molecular weight of the anhydrous material by the hydrated one, then multiply the result by 8.753 g. Solution: NiSO4 anhydrous molecular weight is 154.75 g/mol (anhydrous) NiSO4·7H2O molecular weight is 280.86 g/mol (heptahydrate) So: 154.75/280.86 = 0.55098 The grams quantity produced from 8.753 heptahydrate is (0.55098*8.753) = 4.823 grams anhydrous NiSO4 anhydrous Best wishes AD
Mass in grams if the molar mass of sodium sulfate is 141.98 gramsmoles?
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
How do you calculate moles of atoms in 9.00g of magnesium nitrate?
First, determine the molar mass of magnesium nitrate (Mg(NO3)2) by adding the atomic masses of magnesium, nitrogen, and oxygen. Then, divide the given mass (9.00g) by the molar mass to find the moles of magnesium nitrate.
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
