I assume double displacement reaction. Balanced equation.
3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3
2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4)
= 6.00 moles silver nitrate needed
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Sodium - Na. When silver nitrate is mixed with Sodium Hydroxide, Sodium Iodide, Sodium Phosphate a precipitate forms.
Aqueous sodium phosphate and aqueous iron nitrate react to produce aqueous sodium nitrate and solid iron phosphate.
no reaction
Ag+(aq) + PO4-(aq) -------> Ag3PO4(s)
Produces Silver iodide precipitate and Sodium nitrate
Sodium - Na. When silver nitrate is mixed with Sodium Hydroxide, Sodium Iodide, Sodium Phosphate a precipitate forms.
Aqueous sodium phosphate and aqueous iron nitrate react to produce aqueous sodium nitrate and solid iron phosphate.
no reaction
Silver nitrate and sodium phosphate react to form silver phosphate and sodium nitrate. The balanced equation is 3 AgNO3(aq) + Na3PO4(aq) equals Ag3PO4(s) + 3 NaNO3(aq).
Silver chloride and sodium nitrate.
Ag+(aq) + PO4-(aq) -------> Ag3PO4(s)
sodium phosphate is Na3PO4 cobalt(II) bromide is CoBr2
Produces Silver iodide precipitate and Sodium nitrate
Sodium carbonate is Na2CO3 Silver nitrate is AgNO3
2Na3PO4 + 3Ca(NO3)2 --> 6NaNO3 + Ca3(PO4)2
conclusion of silver nitrate and sodium hyroxide
Silver bromide is insoluble in water and don't react with sodium nitrate.